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From: Luigi on 15 Jun 2010 06:10 Hello, how can I write a method that returns me 10 random numbers from 0 to 20 (included), without repetitions? Thanks a lot. Luigi
From: Soren 'theDiver' Reinke on 15 Jun 2010 07:18 On 15-06-2010 12:10, Luigi wrote: > Hello, > how can I write a method that returns me 10 random numbers from 0 to 20 > (included), without repetitions? If you don't want repetitions they are not real random numbers. You could get the number '15' 10 times in a row, it is possible, but highly unlikely. -- Med venlig hilsen / Best regards Søren Reinke, IDCS #505926, TDI Trimix www.Dykkeren.dk Dive blog with a large gallery
From: Luigi on 15 Jun 2010 09:03 Maybe this one is correct: int[] result = new int[10]; Random random = new Random(); int adding; for (var i = 0; i < 10; i++) { adding = random.Next(1, 20); if (!result.Contains(adding) || !result.Contains(0)) result[i] = adding; else { i--; continue; } } Luigi
From: Luigi on 15 Jun 2010 09:03 I'm trying in this way: int[] result = new int[10]; Random random = new Random(); int adding; for (var i = 0; i < 10; i++) { adding = random.Next(1, 20); if (!result.Contains(adding)) result[i] = adding; } but it seems that give me also the number zero. Luigi
From: Matt on 15 Jun 2010 10:33
On Jun 15, 7:03 am, Luigi <Lu...(a)discussions.microsoft.com> wrote: > Maybe this one is correct: > > int[] result = new int[10]; > Random random = new Random(); > int adding; > > for (var i = 0; i < 10; i++) > { > adding = random.Next(1, 20); > if (!result.Contains(adding) || !result.Contains(0)) > result[i] = adding; > else > { > i--; > continue; > } > > } > > Luigi The easiest way to do what you are trying to accomplish is to create an array of 20 elements, then select a random number in that range. Remove the item (i.e. shift them down one, so that you now have 19 elements). Find a random number in that range, remove it and so forth until you have the number you want. Matt |