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From: Archimedes Plutonium on 2 Apr 2010 01:05 It is a matter of recognizing the disparity or the skewness of the open logarithmic spiral and the associated circle. Now this problem maybe easier than I first thought. By doing it with equicircumference. Equal circumference of a circle is the associated logarithmic spiral of the same distance on the logarithmic spiral. So I define the associated circle with logarithmic spiral as equidistance of circumference. Then for the skewness or disparity, I measure how much of a distance gap between the associated circle and logarithmic spiral. Then I look for the skew or disparity when it equals exactly that of 3 x 10^10 cm/sec, keeping in mind that the circle is in cm and the log-spiral in seconds. So, the final question is , at what associated winding of the logarithmic spiral or the associated circle where the disparity gives 3 x 10^10 cm/sec Now I have not done this yet, only in my mind. It maybe that the circles are time in seconds and the logarithmic spiral is the centimeter measure. It maybe that the speed of light comes out far smaller than 10^500, for it may occur at 10^40 or 10^80 or 10^160. I am hoping it comes out at 10^500. But more than likely it will come out at a number I have not listed. Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |