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From: narke on 13 May 2010 21:29
Hi,

I have a big code, and I cannot get understand some parts of it. Below
is a piece of them:

void determind_corr_value(void)
{
int8_t Leading0;
uint32_t CorrValue;

...

if( CorrValue>0)
{
// Detect bit number of MSB of CorrValue (Leading 0's are
counted)
Leading0 = 1;

while(!(*((int16_t*) &CorrValue + 1) < 0)) // MS_Bit = 0
{
CorrValue <<= 1;
Leading0++;
}

Leading0 -= 8;

// increase the resolution for compensation steps to 0.5Bit by
checking the 2nd bit
//lint -save -e701
Leading0 <<= 1;
if(*((int16_t*) &CorrValue + 1) & 0x4000)
{
Leading0--;
}

// Calculate now the correction value
if( Current < CalibrationData.I_Limit_Corr) {
// low range
Leading0-= (int8_t)Data.Leading0_Corr_Low;

CorrValue = (unsigned)(long)(32768L + ((int16_t)
(CalibrationData.Correction_Low * Leading0)));
} else {
// High range
Leading0-= (int8_t)Data.Leading0_Corr_High;

CorrValue = (unsigned)(long)(32768L + ((int16_t)
(CalibrationData.Correction_High * Leading0)));
}

} else
CorrValue = 32768;

...
}


I guess it was doing some kind of DSP, but not sure what was exactly
going on. Especially, I hope some one have a guess and give me some
hints for my below questions so far:

1. Why Leading0 was assigned as 1 at begin of the process.
2. Why 8 was substracted from the Leading0
3. What means 0.5bit and checking for 2nd bit?
4. Why 32768?

I hope the code indeed implemented some algorithm that is familiar to
some of you.

-
narke
From: Tim Wescott on 13 May 2010 23:01
narke wrote:
> Hi,
>
> I have a big code, and I cannot get understand some parts of it. Below
> is a piece of them:
>

>> snip <<

> -
> narke

In general, when you ask a question and don't like the answer you get,
asking exactly the same question won't bring you any more joy.

--
Tim Wescott
Control system and signal processing consulting
www.wescottdesign.com
From: steveu on 13 May 2010 23:14
>narke wrote:
>> Hi,
>>
>> I have a big code, and I cannot get understand some parts of it. Below
>> is a piece of them:
>>
>
>>> snip <<
>
>> -
>> narke
>
>In general, when you ask a question and don't like the answer you get,
>asking exactly the same question won't bring you any more joy.

There's a good chance it will get you some abusive comments, though. Its a
good strategy for masochists.

Steve

From: narke on 14 May 2010 02:45
On Thu, 13 May 2010 20:01:36 -0700, Tim Wescott <tim(a)seemywebsite.now>
wrote:

>narke wrote:
>> Hi,
>>
>> I have a big code, and I cannot get understand some parts of it. Below
>> is a piece of them:
>>
>
>>> snip <<
>
>> -
>> narke
>
>In general, when you ask a question and don't like the answer you get,
>asking exactly the same question won't bring you any more joy.

Sorry for that. It has something to do with my nntp server. After I
posted the original message and I had not see my message appear on the
groups even serveral hours later. Then, I thought something might be
wrong, so I did a repost.

-
narke
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