From: Saga on
Thanks! Saga

"Armin Zingler" <az.nospam(a)freenet.de> wrote in message
news:ePjlZhK7KHA.4804(a)TK2MSFTNGP02.phx.gbl...
> Am 05.05.2010 21:25, schrieb Saga:
>> Regarding your label control question, loop through all the controls,
>> check to see if it a label then take corresponding action if it is.
>>
>> Something liekthis:
>>
>> For Each oCtrl As Control In Me.Controls
>>
>> 'Is this control a label?
>> If oCtrl.GetType.ToString() = "System.Windows.Forms.Label" Then
>
> If typeof oCtrl is Label Then
>
> is safer and quicker.
>
>> oCtrl.Text = "whatever you need"
>> End If
>>
>> Next
>
>
> --
> Armin