Prev: induction vs recursion
Next: 3D trig problem
From: zuhair on 18 Jun 2010 22:36 After I made a reformulation of Z-Reg. as I presented in the post to this Usenet under the title_ A=Z-Regularity. The following is a parallel formulation but of ZF-Regularity instead of Z-Reg. A" is the set of all sentences (entailed from FOL with identity and membership) by the following non logical axioms: (1) unique replacement:For any formula phi(x,y) not containing the letter B, the following is an axiom: Ar[(Ax c r)AyAz(phi(x,y) & phi(x,z) -> y = z) -> E!BAy(y e B <-> (Ex c r)phi(x,y))]. were c is the subset relation defined in the standard manner. (2) Union: as in Z. (3) Infinity: as in Z. /Theory definition finished. Although I don't have all the formal proofs of this, but I do think A=ZF-Reg. If I am correct then this would be another short reformulation of ZF- Reg. to only three axiom schemes instead of the standard five axiom schemes. Zuhair
|
Pages: 1 Prev: induction vs recursion Next: 3D trig problem |