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From: Obispo de Tolosa on 5 Jun 2010 14:23
...to be valid than Wiles' purported "proof." If it takes 150 pages to write it, even while omitting most of the steps, then it can't possibly be valid.
From: Ostap Bender on 5 Jun 2010 19:08
On Jun 5, 3:23 pm, Obispo de Tolosa <MathMan...(a)hotmail.com> wrote:
> ..to be valid than Wiles' purported "proof." If it takes 150 pages to write it, even while omitting most of the steps, then it can't possibly be valid.

And if a book has more text than pictures - it can't be a good book.
From: JSHIT on 6 Jun 2010 12:46
A hurricane of idiocy, packed into a skull the size of a gnat's rectum.

"Obispo de Tolosa" <MathMan345(a)hotmail.com> wrote in message
news:131718029.285543.1275776652904.JavaMail.root(a)gallium.mathforum.org...

Oh what a surprise. A mathforum imbecile.



From: spudnik on 7 Jun 2010 23:00
it is going to be a while, before the Cliff's Notes version
of Wiles' allaged proof comes out; but, when it does,
you will have quite en entree into a few kinds of math -- iff
you've gotten an elementary (fermatian) proof in hand,
by then.

--Stop BP's and Waxman's capNtrade arbitrage rip-off!
http://wlym.com
From: DRMARJOHN on 9 Jun 2010 11:58
> ...to be valid than Wiles' purported "proof." If it
> takes 150 pages to write it, even while omitting most
> of the steps, then it can't possibly be valid.

this depends on previous submissions.

Start with .5^1/n yields an irrational base for .5.
There is an irrational base minutely above .5^1/n. There is a next irrational base above that, there is a next....until A^n approaches 1.00. This is a complete set of irrational A's.
Each A^n pairs with a B^n to equal 1.00. The B^n may or may not have an irrational B.
This is a complete set of A^n +B^n that have an irrational A.
Likewise, construct all B^n below the irrational base of B^n =.5.
There is an irrational base minutely below .5^1/n. There is a next irrational base below that, there is a next....until A^n approaches .00. This is a complete set of irrational B's.
Each B^n pairs with a A^n to equal 1.00. The A^n may or may not have an irrational A.
This is a complete set of A^n +B^n that have an irrational B.
Martin Johnson 6-9-10
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