From: zuhair on 2 May 2010 17:48 On May 2, 4:26 pm, zuhair <zaljo...(a)gmail.com> wrote: > On May 2, 11:16 am, zuhair <zaljo...(a)gmail.com> wrote: > > > > > On May 1, 12:22 pm, MoeBlee <jazzm...(a)hotmail.com> wrote: > > > > On May 1, 9:42 am, zuhair <zaljo...(a)gmail.com> wrote: > > > > > The quantifiers need not be actually written if writing them > > > > makes no difference to the meaning of the formula > > > > > Example: writing the Extensionality axiom (see below) > > > > [...] > > > > > Extensionality: zx<>zy > x=y > > > > WRONG > > > > Az(zex <-> zey) -> x=y > > > > is NOT equivalent with > > > > Az((zex <-> zey) -> x=y) > > > > Please get a book on the basics of this subject. > > > > MoeBlee > > > I admit my weakness about the basics. > > > A question regarding the basics of this subject, > > > is the following a well formed formula in FOL(e,=): > > > For all x ( For all y ( For all z ((z e x iff z e y) -> x=y) ) ). > > > z is only appearing on the left of the implication, and all variables > > other than > > z are quantified *before* z, so is that acceptable? > > > I might accept the following formula > > > For all z ( For all x ( For all y ((z e x iff z e y) -> x=y) ) ) . > > > since x and y are quantified *after* z, so quantification over z can > > extend as > > far as variables x and y appear in the formula, so it doesn't matter > > if > > z seize to appear after the implication. > > > I just thought that quantification over a variable z closes after the > > last formula > > z or the last variable quantified *after* z appears in. > > > If the answer is yes, which mean that it is a well formed formula, > > then > > in these circumstances we must modify the notation to accommodate for > > that, so > > we either extend the dot notation to cover such cases of > > quantification, or we simply keep the rule of exhaustive > > quantification (as a notation) and always wright the formula z=z on > > the other side to indicate that quantification extend over to the > > other size. > > To clarify the last statement, we can for example wright > > Axyz(zex -> y=x) > > the is written as: xy zx>y=x z=z > > so putting the formula z=z on the other side, will ensure > that quantification is extending over the implication > ( this is the consequence of the rule of Exhaustive quantification > which is adopted in this notation system, which states that:- > > "quantification over a variable z closes after the > last formula in which z or the last variable quantified *after* z > appears in"). More thoroughly: rule of Exhaustive quantification: "quantification over a variable z closes after the last formula in which z or the last variable quantified *after* z appears in; or by the appearance of another quantification over z"). As an example of the last statement, referring to the appearance of another quantification over z is axiom of Foundation x _yx > _yx _cy cx as one can see y is quantified over twice, so the first quantification over y closes just before the implication, while the second quantification over y extends to the end of the formula since c is quantified after y and c appears in the last formula which is cx. so the above formula abbreviates the following: Ax (Ey (y e x) -> Ey (y e x & Ec (c e y & c e x))) so 13 characters instead of 32 characters, almost one third of a reduction! isn't spectacular! Zuhair > > however lets take the statement > > Axyz((zex<->zey)->x=y) > > now this is written as: xy zx<>zy.>x=y > > we don't need to write: xy zx<>zy.>x=y z=z > > since this would be redundant. > > because from the dot after zy , it is clear that > the scope of quantification over z is extending beyond > the implication, otherwise we don't need to place a dot > after zy. > > Zuhair
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