Prev: Vibrating in time and probability of particle location
Next: Can one frame of reference be more absolute than another?
From: mpc755 on 22 Jul 2010 04:49 On Jul 22, 4:40 am, mpc755 <mpc...(a)gmail.com> wrote: > On Jul 21, 11:52 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > On Jul 21, 6:08 pm, colp <c...(a)solder.ath.cx> wrote: > > > > On Jul 22, 10:12 am, PD <thedraperfam...(a)gmail.com> wrote: > > > > > On Jul 21, 4:45 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > What is your point? > > > > > That there is nothing in kinetic theory that points to or relies on an > > > > absolute frame. > > > > (reposting reply to similar assertion by Paul Stowe) > > > > Nope. For example, take two molecules, each with mass m, and separated > > > by distance d. Give the molecules velocities such that they will > > > approach each others center of mass and collide at time t. The > > > calculated energy of the collision will depend on how you measure your > > > velocities. > > > > For either molecule, the relative velocity of the other molecule will > > > be d/t or -d/t. > > > The calculated energy of collision is 1/2 mv^2 = 1/2 m.d^2/t^2, since > > > one molecule is deemed to be stationary. > > > > If, instead, we say that each molecule is moving toward a stationary > > > collision point, then v = d/2t or -d/2t > > > The calculated energy of collision is now 2 * 1/2 mv^2 = m.d^2/4t^2 = > > > 1/2 m.d^2/2t^2 > > > > The two calculations disagree by a factor of two. > > > First of all, the principle of relativity does NOT mean that the VALUE > > of physical quantities are the same in all reference frames. > > > Secondly, please consider what you mean by "energy of collision". The > > energy of collision is NOT the total kinetic energy available. > > > I'll give you an example. Consider a completely inelastic collision > > where two equal masses collide and then stick together. This will > > involve a transformation of kinetic energy into energy of deformation > > (or reconformation), heat, sound, etc. The completely inelastic case > > is the case where the maximum amount of kinetic energy is so > > transformed. > > > I'd like for you to calculate this energy transformed for this > > collision as viewed in two reference frames, just as you've done > > above: One where one of the masses is initially stationary and the > > other is moving at v; and one where both masses are approaching at v/ > > 2. > > > Please remember that to find the final velocities in both cases you > > will need conservation of momentum. > > Why are downgraded photon pairs not required to have opposite angular > momentums in order to conserve the original photons momentum in order > for there to be conservation of momentum in order for there to be > instantaneous action at a distance? > > You still have not answered the questions. > > Explain what occurs physically in nature to cause spacetime to curve > but not move. > Explain what occurs physically in nature which allows a C-60 molecule > to enter, travel through, and exit multiple slits simultaneously > without losing momentum. > Explain what occurs physically in nature when mass converts to energy. > Explain what occurs physically in nature which allows the future to > determine the past. > Explain what occurs physically in nature to cause gravity. > > Dark Matter Displacement explains what occurs physically in nature in > all of the above. > > Dark matter is displaced by matter. > Dark matter is not at rest when displaced. > Displaced dark matter exerts pressure towards the matter. > A moving particle has an associated dark matter displacement wave. > Physical effects caused by matter converting to dark matter is energy. > Mass is conserved. > The future does not determine the past in the physics of nature. > Pressure exerted by displaced dark matter towards matter is gravity. And while you are not answering the above, here is another question for you not to be able to answer: 'Hubble Finds Ghostly Ring of Dark Matter' http://www.nasa.gov/mission_pages/hubble/news/dark_matter_ring_feature.html "Astronomers using NASAs Hubble Space Telescope got a first-hand view of how dark matter behaves during a titanic collision between two galaxy clusters. The wreck created a ripple of dark matter, which is somewhat similar to a ripple formed in a pond when a rock hits the water." Does the ripple eventually reach the Earth? If not then were does the dark matter end and is where the dark matter ends the beginning of a void and if not a void then what are the properties space has where there is no dark matter and how do these properties distinguish this region of space from dark matter? If so then that is evidence dark matter exists from the point of the galaxy cluster collision to the Earth. Dark matter exists between the Earth and the galaxy cluster collision. The ripple will reach the Earth. The ripple propagates through the dark matter which exists between the Earth and the galaxy cluster collision. Dark matter is the medium in which the ripple propagates. Dark matter is the medium in which light waves propagate. The ripple is a gravity wave. The ripple is displaced dark matter. Dark matter is not at rest when displaced. Pressure exerted by displaced dark matter towards matter is gravity.
From: funkenstein on 22 Jul 2010 06:26 On Jul 22, 10:40 am, mpc755 <mpc...(a)gmail.com> wrote: > On Jul 21, 11:52 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > On Jul 21, 6:08 pm, colp <c...(a)solder.ath.cx> wrote: > > > > On Jul 22, 10:12 am, PD <thedraperfam...(a)gmail.com> wrote: > > > > > On Jul 21, 4:45 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > What is your point? > > > > > That there is nothing in kinetic theory that points to or relies on an > > > > absolute frame. > > > > (reposting reply to similar assertion by Paul Stowe) > > > > Nope. For example, take two molecules, each with mass m, and separated > > > by distance d. Give the molecules velocities such that they will > > > approach each others center of mass and collide at time t. The > > > calculated energy of the collision will depend on how you measure your > > > velocities. > > > > For either molecule, the relative velocity of the other molecule will > > > be d/t or -d/t. > > > The calculated energy of collision is 1/2 mv^2 = 1/2 m.d^2/t^2, since > > > one molecule is deemed to be stationary. > > > > If, instead, we say that each molecule is moving toward a stationary > > > collision point, then v = d/2t or -d/2t > > > The calculated energy of collision is now 2 * 1/2 mv^2 = m.d^2/4t^2 = > > > 1/2 m.d^2/2t^2 > > > > The two calculations disagree by a factor of two. > > > First of all, the principle of relativity does NOT mean that the VALUE > > of physical quantities are the same in all reference frames. > > > Secondly, please consider what you mean by "energy of collision". The > > energy of collision is NOT the total kinetic energy available. > > > I'll give you an example. Consider a completely inelastic collision > > where two equal masses collide and then stick together. This will > > involve a transformation of kinetic energy into energy of deformation > > (or reconformation), heat, sound, etc. The completely inelastic case > > is the case where the maximum amount of kinetic energy is so > > transformed. > > > I'd like for you to calculate this energy transformed for this > > collision as viewed in two reference frames, just as you've done > > above: One where one of the masses is initially stationary and the > > other is moving at v; and one where both masses are approaching at v/ > > 2. > > > Please remember that to find the final velocities in both cases you > > will need conservation of momentum. > > Why are downgraded photon pairs not required to have opposite angular > momentums in order to conserve the original photons momentum in order > for there to be conservation of momentum in order for there to be > instantaneous action at a distance? > > You still have not answered the questions. > Looks like he asked first. I like trying to answer, so I'll give your very difficult questions a shot. Why not try to answer some too? > Explain what occurs physically in nature to cause spacetime to curve > but not move. Spacetime does both, only the motion is not detectable. This is gauge invariance, proven by MMX experiment. > Explain what occurs physically in nature which allows a C-60 molecule > to enter, travel through, and exit multiple slits simultaneously > without losing momentum. The "particle" is a wave. > Explain what occurs physically in nature when mass converts to energy. The "mass" actually already was a bundle of energy, with properties we call mass. > Explain what occurs physically in nature which allows the future to > determine the past. Not sure where you are going with this one.. are you talking about antimatter? One answer is that one can use observations at some time T to determine what happened at T-x.. > Explain what occurs physically in nature to cause gravity. G_uv = 8pi T_uv The space-time structures which have mass affect the surrounding space- time like that. [snip spam]
From: mpc755 on 22 Jul 2010 06:58 On Jul 22, 6:26 am, funkenstein <luke.s...(a)gmail.com> wrote: > On Jul 22, 10:40 am, mpc755 <mpc...(a)gmail.com> wrote: > > > > > On Jul 21, 11:52 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > On Jul 21, 6:08 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > On Jul 22, 10:12 am, PD <thedraperfam...(a)gmail.com> wrote: > > > > > > On Jul 21, 4:45 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > > What is your point? > > > > > > That there is nothing in kinetic theory that points to or relies on an > > > > > absolute frame. > > > > > (reposting reply to similar assertion by Paul Stowe) > > > > > Nope. For example, take two molecules, each with mass m, and separated > > > > by distance d. Give the molecules velocities such that they will > > > > approach each others center of mass and collide at time t. The > > > > calculated energy of the collision will depend on how you measure your > > > > velocities. > > > > > For either molecule, the relative velocity of the other molecule will > > > > be d/t or -d/t. > > > > The calculated energy of collision is 1/2 mv^2 = 1/2 m.d^2/t^2, since > > > > one molecule is deemed to be stationary. > > > > > If, instead, we say that each molecule is moving toward a stationary > > > > collision point, then v = d/2t or -d/2t > > > > The calculated energy of collision is now 2 * 1/2 mv^2 = m.d^2/4t^2 = > > > > 1/2 m.d^2/2t^2 > > > > > The two calculations disagree by a factor of two. > > > > First of all, the principle of relativity does NOT mean that the VALUE > > > of physical quantities are the same in all reference frames. > > > > Secondly, please consider what you mean by "energy of collision". The > > > energy of collision is NOT the total kinetic energy available. > > > > I'll give you an example. Consider a completely inelastic collision > > > where two equal masses collide and then stick together. This will > > > involve a transformation of kinetic energy into energy of deformation > > > (or reconformation), heat, sound, etc. The completely inelastic case > > > is the case where the maximum amount of kinetic energy is so > > > transformed. > > > > I'd like for you to calculate this energy transformed for this > > > collision as viewed in two reference frames, just as you've done > > > above: One where one of the masses is initially stationary and the > > > other is moving at v; and one where both masses are approaching at v/ > > > 2. > > > > Please remember that to find the final velocities in both cases you > > > will need conservation of momentum. > > > Why are downgraded photon pairs not required to have opposite angular > > momentums in order to conserve the original photons momentum in order > > for there to be conservation of momentum in order for there to be > > instantaneous action at a distance? > > > You still have not answered the questions. > > Looks like he asked first. I like trying to answer, so I'll give your > very difficult questions a shot. Why not try to answer some too? > I will answer these very simple questions. > > Explain what occurs physically in nature to cause spacetime to curve > > but not move. > > Spacetime does both, only the motion is not detectable. This is gauge > invariance, proven by MMX experiment. > 'Gauge theory' http://en.wikipedia.org/wiki/Gauge_theory "In physics, a gauge theory is a type of field theory in which the Lagrangian is invariant under a continuous group of local transformations." Explain what physically occurs in nature to cause the 'field' to curve and what does the 'field' physically exist as? If not then is the 'field' a void? Is the 'field' material'? If not then how does the 'field' curve? Dark matter displaced by matter is what you describe as the curvature of spacetime. > > Explain what occurs physically in nature which allows a C-60 molecule > > to enter, travel through, and exit multiple slits simultaneously > > without losing momentum. > > The "particle" is a wave. > What physically occurs in nature to cause the 'particle' to always be detected exiting a single slit? The particle is always detected exiting a single slit because the particle always exits a single slit. The moving particle has an associated dark matter displacement wave. The particle enters and exits a single slit. The associated dark matter displacement wave enters and exits multiple slits. The dark matter displacement wave creates interference upon exiting the slits which alters the direction the particle travels. Detecting the particle causes decoherence of the associated dark matter displacement wave (i.e. turns the wave into chop) and there is no interference. > > Explain what occurs physically in nature when mass converts to energy. > > The "mass" actually already was a bundle of energy, with properties we > call mass. > A change in state of mass is energy. Matter converts to dark matter. The effects this transition has on three dimensional space is energy. > > Explain what occurs physically in nature which allows the future to > > determine the past. > > Not sure where you are going with this one.. are you talking about > antimatter? One answer is that one can use observations at some time > T to determine what happened at T-x.. > Has to do with a double slit thought experiment. Will follow up on another post. > > Explain what occurs physically in nature to cause gravity. > > G_uv = 8pi T_uv > > The space-time structures which have mass affect the surrounding space- > time like that. > Pressure exerted by displaced dark matter towards matter is gravity.
From: mpc755 on 22 Jul 2010 07:32 On Jul 22, 6:58 am, mpc755 <mpc...(a)gmail.com> wrote: > On Jul 22, 6:26 am, funkenstein <luke.s...(a)gmail.com> wrote: > > > > > On Jul 22, 10:40 am, mpc755 <mpc...(a)gmail.com> wrote: > > > > On Jul 21, 11:52 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > On Jul 21, 6:08 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > > On Jul 22, 10:12 am, PD <thedraperfam...(a)gmail.com> wrote: > > > > > > > On Jul 21, 4:45 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > > > What is your point? > > > > > > > That there is nothing in kinetic theory that points to or relies on an > > > > > > absolute frame. > > > > > > (reposting reply to similar assertion by Paul Stowe) > > > > > > Nope. For example, take two molecules, each with mass m, and separated > > > > > by distance d. Give the molecules velocities such that they will > > > > > approach each others center of mass and collide at time t. The > > > > > calculated energy of the collision will depend on how you measure your > > > > > velocities. > > > > > > For either molecule, the relative velocity of the other molecule will > > > > > be d/t or -d/t. > > > > > The calculated energy of collision is 1/2 mv^2 = 1/2 m.d^2/t^2, since > > > > > one molecule is deemed to be stationary. > > > > > > If, instead, we say that each molecule is moving toward a stationary > > > > > collision point, then v = d/2t or -d/2t > > > > > The calculated energy of collision is now 2 * 1/2 mv^2 = m.d^2/4t^2 = > > > > > 1/2 m.d^2/2t^2 > > > > > > The two calculations disagree by a factor of two. > > > > > First of all, the principle of relativity does NOT mean that the VALUE > > > > of physical quantities are the same in all reference frames. > > > > > Secondly, please consider what you mean by "energy of collision". The > > > > energy of collision is NOT the total kinetic energy available. > > > > > I'll give you an example. Consider a completely inelastic collision > > > > where two equal masses collide and then stick together. This will > > > > involve a transformation of kinetic energy into energy of deformation > > > > (or reconformation), heat, sound, etc. The completely inelastic case > > > > is the case where the maximum amount of kinetic energy is so > > > > transformed. > > > > > I'd like for you to calculate this energy transformed for this > > > > collision as viewed in two reference frames, just as you've done > > > > above: One where one of the masses is initially stationary and the > > > > other is moving at v; and one where both masses are approaching at v/ > > > > 2. > > > > > Please remember that to find the final velocities in both cases you > > > > will need conservation of momentum. > > > > Why are downgraded photon pairs not required to have opposite angular > > > momentums in order to conserve the original photons momentum in order > > > for there to be conservation of momentum in order for there to be > > > instantaneous action at a distance? > > > > You still have not answered the questions. > > > Looks like he asked first. I like trying to answer, so I'll give your > > very difficult questions a shot. Why not try to answer some too? > > I will answer these very simple questions. > > > > Explain what occurs physically in nature to cause spacetime to curve > > > but not move. > > > Spacetime does both, only the motion is not detectable. This is gauge > > invariance, proven by MMX experiment. > > 'Gauge theory'http://en.wikipedia.org/wiki/Gauge_theory > > "In physics, a gauge theory is a type of field theory in which the > Lagrangian is invariant under a continuous group of local > transformations." > > Explain what physically occurs in nature to cause the 'field' to curve > and what does the 'field' physically exist as? If not then is the > 'field' a void? Is the 'field' material'? If not then how does the > 'field' curve? > > Dark matter displaced by matter is what you describe as the curvature > of spacetime. > > > > Explain what occurs physically in nature which allows a C-60 molecule > > > to enter, travel through, and exit multiple slits simultaneously > > > without losing momentum. > > > The "particle" is a wave. > > What physically occurs in nature to cause the 'particle' to always be > detected exiting a single slit? > > The particle is always detected exiting a single slit because the > particle always exits a single slit. The moving particle has an > associated dark matter displacement wave. The particle enters and > exits a single slit. The associated dark matter displacement wave > enters and exits multiple slits. The dark matter displacement wave > creates interference upon exiting the slits which alters the direction > the particle travels. Detecting the particle causes decoherence of the > associated dark matter displacement wave (i.e. turns the wave into > chop) and there is no interference. > > > > Explain what occurs physically in nature when mass converts to energy.. > > > The "mass" actually already was a bundle of energy, with properties we > > call mass. > > A change in state of mass is energy. Matter converts to dark matter. > The effects this transition has on three dimensional space is energy. > > > > Explain what occurs physically in nature which allows the future to > > > determine the past. > > > Not sure where you are going with this one.. are you talking about > > antimatter? One answer is that one can use observations at some time > > T to determine what happened at T-x.. > > Has to do with a double slit thought experiment. Will follow up on > another post. The slits in a double slit experiment are the length the particle travels in a year. The particle enters the slit(s). Six months later detectors are placed at the exits to the slits. The particle is always detected exiting a single slit. The slits in a double slit experiment are the length the particle travels in a year. The particle enters the slit(s). Six months later detectors are placed at the exits to the slits. Three months later, or nine months since the particle entered the slit(s) the detectors are removed from the exits. Repeat and the particle creates an interference pattern. The poster I was asking the question of insists the particle enters one slit or multiple slits depending upon there being detectors at the exits to the slits when the particle exits the slits a year in the future. In Dark Matter Displacement the particle is always detected exiting a single slit because the particle always enters and exits a single slit and it is the associated dark matter displacement wave which enters and exits multiple slits and creates interference upon exiting the slits which alters the direction the particle travels. > > > > Explain what occurs physically in nature to cause gravity. > > > G_uv = 8pi T_uv > > > The space-time structures which have mass affect the surrounding space- > > time like that. > > Pressure exerted by displaced dark matter towards matter is gravity.
From: mpc755 on 23 Jul 2010 00:42 On Jul 22, 4:49 am, mpc755 <mpc...(a)gmail.com> wrote: > On Jul 22, 4:40 am, mpc755 <mpc...(a)gmail.com> wrote: > > > > > On Jul 21, 11:52 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > On Jul 21, 6:08 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > On Jul 22, 10:12 am, PD <thedraperfam...(a)gmail.com> wrote: > > > > > > On Jul 21, 4:45 pm, colp <c...(a)solder.ath.cx> wrote: > > > > > > What is your point? > > > > > > That there is nothing in kinetic theory that points to or relies on an > > > > > absolute frame. > > > > > (reposting reply to similar assertion by Paul Stowe) > > > > > Nope. For example, take two molecules, each with mass m, and separated > > > > by distance d. Give the molecules velocities such that they will > > > > approach each others center of mass and collide at time t. The > > > > calculated energy of the collision will depend on how you measure your > > > > velocities. > > > > > For either molecule, the relative velocity of the other molecule will > > > > be d/t or -d/t. > > > > The calculated energy of collision is 1/2 mv^2 = 1/2 m.d^2/t^2, since > > > > one molecule is deemed to be stationary. > > > > > If, instead, we say that each molecule is moving toward a stationary > > > > collision point, then v = d/2t or -d/2t > > > > The calculated energy of collision is now 2 * 1/2 mv^2 = m.d^2/4t^2 = > > > > 1/2 m.d^2/2t^2 > > > > > The two calculations disagree by a factor of two. > > > > First of all, the principle of relativity does NOT mean that the VALUE > > > of physical quantities are the same in all reference frames. > > > > Secondly, please consider what you mean by "energy of collision". The > > > energy of collision is NOT the total kinetic energy available. > > > > I'll give you an example. Consider a completely inelastic collision > > > where two equal masses collide and then stick together. This will > > > involve a transformation of kinetic energy into energy of deformation > > > (or reconformation), heat, sound, etc. The completely inelastic case > > > is the case where the maximum amount of kinetic energy is so > > > transformed. > > > > I'd like for you to calculate this energy transformed for this > > > collision as viewed in two reference frames, just as you've done > > > above: One where one of the masses is initially stationary and the > > > other is moving at v; and one where both masses are approaching at v/ > > > 2. > > > > Please remember that to find the final velocities in both cases you > > > will need conservation of momentum. > > > Why are downgraded photon pairs not required to have opposite angular > > momentums in order to conserve the original photons momentum in order > > for there to be conservation of momentum in order for there to be > > instantaneous action at a distance? > > > You still have not answered the questions. > > > Explain what occurs physically in nature to cause spacetime to curve > > but not move. > > Explain what occurs physically in nature which allows a C-60 molecule > > to enter, travel through, and exit multiple slits simultaneously > > without losing momentum. > > Explain what occurs physically in nature when mass converts to energy. > > Explain what occurs physically in nature which allows the future to > > determine the past. > > Explain what occurs physically in nature to cause gravity. > > > Dark Matter Displacement explains what occurs physically in nature in > > all of the above. > > > Dark matter is displaced by matter. > > Dark matter is not at rest when displaced. > > Displaced dark matter exerts pressure towards the matter. > > A moving particle has an associated dark matter displacement wave. > > Physical effects caused by matter converting to dark matter is energy. > > Mass is conserved. > > The future does not determine the past in the physics of nature. > > Pressure exerted by displaced dark matter towards matter is gravity. > > And while you are not answering the above, here is another question > for you not to be able to answer: > > 'Hubble Finds Ghostly Ring of Dark Matter'http://www.nasa.gov/mission_pages/hubble/news/dark_matter_ring_featur... > > "Astronomers using NASAs Hubble Space Telescope got a first-hand view > of how dark matter behaves during a titanic collision between two > galaxy clusters. The wreck created a ripple of dark matter, which is > somewhat similar to a ripple formed in a pond when a rock hits the > water." > > Does the ripple eventually reach the Earth? If not then were does the > dark matter end and is where the dark matter ends the beginning of a > void and if not a void then what are the properties space has where > there is no dark matter and how do these properties distinguish this > region of space from dark matter? If so then that is evidence dark > matter exists from the point of the galaxy cluster collision to the > Earth. > <crickets> > Dark matter exists between the Earth and the galaxy cluster collision. > The ripple will reach the Earth. > The ripple propagates through the dark matter which exists between the > Earth and the galaxy cluster collision. > Dark matter is the medium in which the ripple propagates. > Dark matter is the medium in which light waves propagate. > > The ripple is a gravity wave. > The ripple is displaced dark matter. > Dark matter is not at rest when displaced. > Pressure exerted by displaced dark matter towards matter is gravity. >
First
|
Prev
|
Next
|
Last
Pages: 1 2 3 Prev: Vibrating in time and probability of particle location Next: Can one frame of reference be more absolute than another? |