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From: Jeffrey Wilson Jeffrey on 2 Mar 2010 19:22
I'm new to Access and have a Table where I'd like to put in a Beginning date
that an item was sent out on rent, and then put a date where it was returned
from being on rent. I'd like to set up a record that sums the number of days
that item was out, based on the previous two records.

I'm looking for this to be shown in the Form view, as a user is putting in
the dates.

Thank you
From: Steve on 2 Mar 2010 20:00
Jeffrey,

Look at the DateDiff function in the Help file.

Steve
santus(a)penn.com


"Jeffrey Wilson" <Jeffrey Wilson(a)discussions.microsoft.com> wrote in message
news:1899A597-DCFD-4F4E-A999-3E1FABE44EEF(a)microsoft.com...
> I'm new to Access and have a Table where I'd like to put in a Beginning
> date
> that an item was sent out on rent, and then put a date where it was
> returned
> from being on rent. I'd like to set up a record that sums the number of
> days
> that item was out, based on the previous two records.
>
> I'm looking for this to be shown in the Form view, as a user is putting in
> the dates.
>
> Thank you


From: John W. Vinson on 2 Mar 2010 21:01
On Tue, 2 Mar 2010 16:22:14 -0800, Jeffrey Wilson <Jeffrey
Wilson(a)discussions.microsoft.com> wrote:

>I'm new to Access and have a Table where I'd like to put in a Beginning date
>that an item was sent out on rent, and then put a date where it was returned
>from being on rent. I'd like to set up a record that sums the number of days
>that item was out, based on the previous two records.
>
>I'm looking for this to be shown in the Form view, as a user is putting in
>the dates.
>
>Thank you

The time duration should be calculated on the fly, NOT stored in any table: if
you store both dates and the duration then any of the fields could be edited,
giving anomalies such as a DateOut of #2/1/2010#, DateReturned of #3/2/2010#,
and a duration of 3 days!

Instead, just store the dateOut and DateReturned, and set the Control Source
of a textbox on the form to

=DateDiff("d", [DateOut], [DateReturned])

If you want to see the days out up to today's date if the item has not yet
been returned, i.e. DateReturned is NULL, use

=DateDiff("d", [DateOut], NZ([DateReturned], Date()))
--

John W. Vinson [MVP]
From: Jeffrey Wilson on 4 Mar 2010 14:08
John,

Thank you for the expression! I had been reading the help files on the
DateDiff and just wasn't piecing it together. That helped me understand it
better and seems to work great!

Many Thanks
Jeffrey Wilson

"John W. Vinson" wrote:

> On Tue, 2 Mar 2010 16:22:14 -0800, Jeffrey Wilson <Jeffrey
> Wilson(a)discussions.microsoft.com> wrote:
>
> >I'm new to Access and have a Table where I'd like to put in a Beginning date
> >that an item was sent out on rent, and then put a date where it was returned
> >from being on rent. I'd like to set up a record that sums the number of days
> >that item was out, based on the previous two records.
> >
> >I'm looking for this to be shown in the Form view, as a user is putting in
> >the dates.
> >
> >Thank you
>
> The time duration should be calculated on the fly, NOT stored in any table: if
> you store both dates and the duration then any of the fields could be edited,
> giving anomalies such as a DateOut of #2/1/2010#, DateReturned of #3/2/2010#,
> and a duration of 3 days!
>
> Instead, just store the dateOut and DateReturned, and set the Control Source
> of a textbox on the form to
>
> =DateDiff("d", [DateOut], [DateReturned])
>
> If you want to see the days out up to today's date if the item has not yet
> been returned, i.e. DateReturned is NULL, use
>
> =DateDiff("d", [DateOut], NZ([DateReturned], Date()))
> --
>
> John W. Vinson [MVP]
> .
>
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