From: Han de Bruijn on
On 13 apr, 12:21, Tonico <Tonic...(a)yahoo.com> wrote:
> On Apr 13, 10:35 am, Han de Bruijn <umum...(a)gmail.com> wrote:
>
>
>
>
>
> > On 12 apr, 20:18, A N Niel <ann...(a)nym.alias.net.invalid> wrote:
>
> > > In article <20100412134614.421...(a)newsreader.com>, David W. Cantrell
>
> > > <DWCantr...(a)sigmaxi.net> wrote:
> > > > Maury Barbato <mauriziobarb...(a)aruba.it> wrote:
> > > > > Hello,
> > > > > consider the infinite product
>
> > > > > product_{n=1}^Infty [1 + (n^(-2))],
>
> > > > > which is easily seen to converge taking the logarithm.
> > > > > Someone knows th exact value of the product?
>
> > > > sinh(pi)/pi
>
> > > > David
>
> > > and, more generally, for any complex z, we have:
> > > sin(pi z) = pi z product(n=1 to infinity)(1-z^2/n^2)
>
> > Wonder if there are OTHER infinite products NOT resemblant to this one
> > because I've seen this one so many times ..
>
> > Han de Bruijn-
>
> Wonder no more, my dear HdB:
>
> http://pi.physik.uni-bonn.de/~dieckman/InfProd/InfProd.html#Infinitex...
>
> You're welcome ( this googling thingy is marvelous...;) )
>
> Tonio

Hey, that's nice! Thanks, Tonio:

Han de Bruijn
From: Maury Barbato on
A N Niel wrote:

> In article <20100412134614.421$wX(a)newsreader.com>,
> David W. Cantrell
> <DWCantrell(a)sigmaxi.net> wrote:
>
> > Maury Barbato <mauriziobarbato(a)aruba.it> wrote:
> > > Hello,
> > > consider the infinite product
> > >
> > > product_{n=1}^Infty [1 + (n^(-2))],
> > >
> > > which is easily seen to converge taking the
> logarithm.
> > > Someone knows th exact value of the product?
> >
> > sinh(pi)/pi
> >
> > David
>
> and, more generally, for any complex z, we have:
> sin(pi z) = pi z product(n=1 to infinity)(1-z^2/n^2)

Thank you very much for your help, David and Niel.
Friendly Regards,
Maury Barbato