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From: Vladimir Bondarenko on 9 Aug 2010 07:03 Hello, Sqrt[2*(1 + Sqrt[2])]* (AppellF1[-1/2,-1/2,-1/2,1/2,-2*(Sqrt[2]+1),2*(Sqrt[2]-1)] + 4*AppellF1[1/2,1/2,1/2,3/2,-2*(Sqrt[2]+1),2*(Sqrt[2]-1)]) + 4*(-EllipticE[-3 - 2*Sqrt[2]] + (1 + Sqrt[2])*EllipticE[Pi/8, 4 - 2*Sqrt[2]] + EllipticK[-3 - 2*Sqrt[2]]) = ? Cheers, Vladimir Bondarenko Co-founder, CEO, Mathematical Director http://www.cybertester.com/ Cyber Tester Ltd. ---------------------------------------------------------------- "We must understand that technologies like these are the way of the future." ---------------------------------------------------------------- ---------------------------------------------------------------- http://groups.google.com/group/sci.math/msg/9f429c3ea5649df5 "...... the challenges imply that a solution is built within the framework of the existent CAS functions & built-in definitions." ---------------------------------------------------------------- ---------------------------------------------------------------- |