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From: Vladimir Bondarenko on 27 Jul 2010 17:22
Hello,

Mathematica:

(-1)^(5/12) EllipticK[-(-1)^(2/3)] -
(-1)^(5/12) EllipticPi[-(-1)^(5/6)/Sqrt[3], -(-1)^(2/3)] -
(-1)^(7/12) EllipticPi[(3 + I Sqrt[3])/2, (1 + I Sqrt[3])/2]

Maple:

(-1)^(5/12)*EllipticK(sqrt(-(-1)^(2/3)))-
(-1)^(5/12)*EllipticPi(-(-1)^(5/6)/sqrt(3),sqrt(-(-1)^(2/3)))-
(-1)^(7/12)*EllipticPi((3+I*sqrt(3))/2,sqrt((1+I*sqrt(3))/2))

Can you "elementarize" this ?

Cheers,

Vladimir Bondarenko

Co-founder, CEO, Mathematical Director

http://www.cybertester.com/ Cyber Tester Ltd.

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"We must understand that technologies
like these are the way of the future."

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http://groups.google.com/group/sci.math/msg/9f429c3ea5649df5

"...... the challenges imply that a solution is built within the
framework of the existent CAS functions & built-in definitions."

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From: Vladimir Bondarenko on 1 Aug 2010 03:06
On Jul 28, 12:22 am, Vladimir Bondarenko <v...(a)cybertester.com> wrote:
> Hello,
>
> Mathematica:
>
> (-1)^(5/12) EllipticK[-(-1)^(2/3)] -
> (-1)^(5/12) EllipticPi[-(-1)^(5/6)/Sqrt[3], -(-1)^(2/3)] -
> (-1)^(7/12) EllipticPi[(3 + I Sqrt[3])/2, (1 + I Sqrt[3])/2]
>
> Maple:
>
> (-1)^(5/12)*EllipticK(sqrt(-(-1)^(2/3)))-
> (-1)^(5/12)*EllipticPi(-(-1)^(5/6)/sqrt(3),sqrt(-(-1)^(2/3)))-
> (-1)^(7/12)*EllipticPi((3+I*sqrt(3))/2,sqrt((1+I*sqrt(3))/2))
>
> Can you "elementarize" this ?
>
> Cheers,
>
> Vladimir Bondarenko
>
> Co-founder, CEO, Mathematical Director
>
> http://www.cybertester.com/ Cyber Tester Ltd.
>
> ----------------------------------------------------------------
>
> "We must understand that technologies
> like these are the way of the future."
>
> ----------------------------------------------------------------
> ----------------------------------------------------------------
>
> http://groups.google.com/group/sci.math/msg/9f429c3ea5649df5
>
> "...... the challenges imply that a solution is built within the
> framework of the existent CAS functions & built-in definitions."
>
> ----------------------------------------------------------------
> ----------------------------------------------------------------

Hint: The answer = Pi/(2 3^(3/4))

:)
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