From: Virgil on
In article <1151441901.524144.290280(a)m73g2000cwd.googlegroups.com>,
mueckenh(a)rz.fh-augsburg.de wrote:

> Virgil schrieb:
>
>
> > While that numbers may not have a known or even knowable decimal
> > expansion, the fact that you have named that one validates its existence.
>
> So the number pipifax which I just named does exist too?
>
> What is its approximate size?
>
> Regards, WM

It's about that big!
From: Virgil on
In article <1151442095.686342.310050(a)m73g2000cwd.googlegroups.com>,
mueckenh(a)rz.fh-augsburg.de wrote:

> Virgil schrieb:
>
>
> > Which digits in 0.111... = sum_{n in N} 10 ^(-n) are not indexed by
> > members of N?
>
> Best you can see it here:
>
> 1 0.1
> 2 0.11
> 3 0.111
> ... ...
> n 0.111...n
> ... ...
> omega 0.111...omega

Your "n 0,111...n" does not fit the previous pattern, as it contains
digits other than 1's, and omega is not a member of the sequence
0,1,2,...

So your example is cooked, and is meaningless.

>
> It is true that the set of natural numbers is not an actually infinite
> set but a potentially infinite i.e. always finite but not limited by a
> finite threshold.

In ZFC and NBG, which are the only systems under discussion here, there
is no such potentiality not actualized.
> >
>
> 0.0
> 0.1
> 0.11
> 0.111
> ...
> The diagonal number 0.111... can *only then* be different from any
> number of the list, if it has more digits 1 than any list number.

Actually, it is a deliberately ambiguous representation of an arbitrary
member of the list, sort of like a variable.
From: Virgil on
In article <1151442257.587808.324200(a)m73g2000cwd.googlegroups.com>,
mueckenh(a)rz.fh-augsburg.de wrote:

> Virgil schrieb:
>
> > > We cannot write or read an unending string. The assumption, such
> > > strings existed, is wrong.
> >
> > The assumption that for every rational number we can describe precisely
> > the unending string representing it is right.
> > So some endless strings exist, even if only in the imagination.
> > But that is where all mathematics exists!
>
> Yes. And because it exists only there, nothing does exist, which does
> not precisely exist there. Such a nothing is an unending string. You
> may believe or even be convinced that it does exist, but you are wrong.
> Numbers like 5 or 1/3 do, but numbers like pi do not.

No numbers exist outside of the imagination. All numbers that we can
imagine exist within it. Though whether there is a viable arithmetic for
them depends on out imagining a lot more.
> > > >
> > >
> > > All numbers you will ever produce can be listed. That is enough.
> >
> > In what list? Give me any listing which you claim lists every real, and
> > I will give you a rule producing one nonmember of that list for every
> > subset of N.
>
> And that number can also be inserted in the list "g".

"That number" is not just one number, it is a massive collection of
numbers with one for each subset of the power set of the set of naturals.
And that set can be specified by a fairly simple rule of construction.
>
> Regards, WM
From: Virgil on
In article <1151442361.464301.177450(a)u72g2000cwu.googlegroups.com>,
mueckenh(a)rz.fh-augsburg.de wrote:

> Daryl McCullough schrieb:
>
> > >f: 1 --> {1} and a --> { } with K_f = { },
> > >g: 1 --> { } and a --> {1} with K_g = {1}.
> > >Here we have certainly no problem with lacking elements.
> >
> > The claim made by Cantor is that for any set A, there is
> > no surjection from A to P(A). Of course, if you construct
> > a new set B by adding extra elements to A, then there might
> > be a surjection from B to P(A). But why is that relevant?
>
> To show you that the condition K is impossible, independent of any
> surjectivity.
> Map |R (including |N) on P(|N) with the only condition that a natural
> number has to be mapped on that set K e P(|N) which contains all
> natural numbers which are not mapped on sets containing them. You see:
> It is impossible a condition.


There are all sorts of impossible conditions, most of which are
irrelevant to anything.

What is the alleged relevance of this one?
From: mueckenh on

Daryl McCullough schrieb:

> mueckenh(a)rz.fh-augsburg.de says...
>
> >Daryl McCullough schrieb:
>
> >> So the answer is no? There is no function f enumerating
> >> all the real numbers? So the reals are uncountable.
> >
> >There is a mathematical form containing all real numbers of [0, 1]. In
> >binary representation it is given here. Why not call it a function in
> >an extended sense?
>
> The question is this: does it map the naturals onto the real numbers
> in [0,1] such that every real number is in its image?
>
> In particular, with your representation, which natural number maps
> to the real 1/3?

It is not necessary to know this natural number (which remains unknown
or does not exist) in oder to prove that the infinite branches of the
tree are countable.

Regards, WM

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