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From: Paul Halliday on 30 Jul 2010 14:36 I have a query that may not always return a result for a value, I need to reflect this with a "0". I am trying to overcome this by doing this (the keys are ID's): while ($row = mysql_fetch_row($statusQuery)) { $cat = array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0); switch ($row[1]) { case 0: $cat[0] = $row[0]; break; case 1: $cat[1] = $row[0]; break; case 11: $cat[11] = $row[0]; break; case 12: $cat[12] = $row[0]; break; case 13: $cat[13] = $row[0]; break; case 14: $cat[14] = $row[0]; break; case 15: $cat[15] = $row[0]; break; case 16: $cat[16] = $row[0]; break; case 17: $cat[17] = $row[0]; break; case 19: $cat[19] = $row[0]; break; } print_r($cat); } Which gives me this: Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15] => 0 [16] => 0 [17] => 0 [19] => 0 ) Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15] => 30 [16] => 0 [17] => 0 [19] => 0 ) The query only return 2 rows: 15 | 30 0 | 15547 What am I doing wrong? Is there a more elegant way to achieve what I want? Thanks. -- Paul Halliday Ideation | Individualization | Learner | Achiever | Analytical http://www.pintumbler.org
From: Joshua Kehn on 30 Jul 2010 14:44 On Jul 30, 2010, at 2:36 PM, Paul Halliday wrote: > I have a query that may not always return a result for a value, I need > to reflect this with a "0". I am trying to overcome this by doing this > (the keys are ID's): > > while ($row = mysql_fetch_row($statusQuery)) { > > $cat = array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0); > > switch ($row[1]) { > case 0: $cat[0] = $row[0]; break; > case 1: $cat[1] = $row[0]; break; > case 11: $cat[11] = $row[0]; break; > case 12: $cat[12] = $row[0]; break; > case 13: $cat[13] = $row[0]; break; > case 14: $cat[14] = $row[0]; break; > case 15: $cat[15] = $row[0]; break; > case 16: $cat[16] = $row[0]; break; > case 17: $cat[17] = $row[0]; break; > case 19: $cat[19] = $row[0]; break; > } > > print_r($cat); > } > > Which gives me this: > > Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 > [15] => 0 [16] => 0 [17] => 0 [19] => 0 ) > Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15]s > => 30 [16] => 0 [17] => 0 [19] => 0 ) > > The query only return 2 rows: > > 15 | 30 > 0 | 15547 > > What am I doing wrong? Is there a more elegant way to achieve what I want? > > Thanks. > > -- > Paul Halliday > Ideation | Individualization | Learner | Achiever | Analytical > http://www.pintumbler.org > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > Paul- Why not say: $cat = array(); if(isset($row[1]) { $cat[$row[1]] = $row[0]; } print_r($cat); Regards, -Josh
From: Paul Halliday on 30 Jul 2010 14:54 On Fri, Jul 30, 2010 at 3:44 PM, Joshua Kehn <josh.kehn(a)gmail.com> wrote: > > On Jul 30, 2010, at 2:36 PM, Paul Halliday wrote: > >> I have a query that may not always return a result for a value, I need >> to reflect this with a "0". I am trying to overcome this by doing this >> (the keys are ID's): >> >> while ($row = mysql_fetch_row($statusQuery)) { >> >> $cat = array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0); >> >> switch ($row[1]) { >> case 0: $cat[0] = $row[0]; break; >> case 1: $cat[1] = $row[0]; break; >> case 11: $cat[11] = $row[0]; break; >> case 12: $cat[12] = $row[0]; break; >> case 13: $cat[13] = $row[0]; break; >> case 14: $cat[14] = $row[0]; break; >> case 15: $cat[15] = $row[0]; break; >> case 16: $cat[16] = $row[0]; break; >> case 17: $cat[17] = $row[0]; break; >> case 19: $cat[19] = $row[0]; break; >> } >> >> print_r($cat); >> } >> >> Which gives me this: >> >> Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 >> [15] => 0 [16] => 0 [17] => 0 [19] => 0 ) >> Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15]s >> => 30 [16] => 0 [17] => 0 [19] => 0 ) >> >> The query only return 2 rows: >> >> 15 | 30 >> 0 | 15547 >> >> What am I doing wrong? Is there a more elegant way to achieve what I want? >> >> Thanks. >> >> -- >> Paul Halliday >> Ideation | Individualization | Learner | Achiever | Analytical >> http://www.pintumbler.org >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> > > Paul- > > Why not say: > > $cat = array(); > if(isset($row[1]) > { > $cat[$row[1]] = $row[0]; > } > > print_r($cat); > > Regards, > > -Josh I need the results that don't have values assigned though. ex: c = 0 h = 9 t = 0 f = 21 Even if the query returned only: h = 9 f = 21
From: Joshua Kehn on 30 Jul 2010 15:06
On Jul 30, 2010, at 3:03 PM, Paul Halliday wrote: >> >> Paul- >> >> Why are those values not defaulted to 0 in the database? >> >> Regards, >> >> -Josh >> >> > > They are defaulted, the query is grouping: > > select count(status) as count, status from table group by status order > by status desc; Paul- Correct, so stuff with a status of 0 will still show up unless I'm missing something. Regards, -Josh |