Beginner's question
in [Matlab]
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From: Takis on 24 Feb 2010 18:15 Hi there, I have a a vector V=[X Y Z] (438x3) and the following array A=time: [438x1 double] pos: [438x3 double] Vel: [438x3 double] F: [438x4 double] I would like to ask you please how i should write a for loop so the following function to run through the data row by row. [Output] = function(V,A) Many thanks in advance!
From: ImageAnalyst on 24 Feb 2010 18:19 And what kind of data do you want to be in the "Output" argument?
From: Takis on 24 Feb 2010 18:30 ImageAnalyst <imageanalyst(a)mailinator.com> wrote in message <270e62f8-5a36-4982-9296-621ad457411f(a)z11g2000yqz.googlegroups.com>... > And what kind of data do you want to be in the "Output" argument? Thanks a lot for your reply!! I would like to be a 438 x 4 vector!! Time X Y Z
From: Nathan on 24 Feb 2010 18:40 On Feb 24, 3:30 pm, "Takis " <dts...(a)remove.this.vip.gr> wrote: > ImageAnalyst <imageanal...(a)mailinator.com> wrote in message <270e62f8-5a36-4982-9296-621ad4574...(a)z11g2000yqz.googlegroups.com>... > > And what kind of data do you want to be in the "Output" argument? > > Thanks a lot for your reply!! I would like to be a 438 x 4 vector!! > > Time X Y Z If you just want your Output variable to contain Time X Y Z, then you can simple do this (assuming you know X, Y, and Z, and assuming A is a structure with time, pos, Vel, and F as arrays within this structure) Output = [A.time X Y Z] If this doesn't work for you, could you please be more specific as to what you are looking for? Why do you want a function to go through your data row by row? What is the purpose for that? -Nathan
From: ImageAnalyst on 24 Feb 2010 18:41
Takis OK, how about this: function Output = ReturnOutput(V, A) Output = rand(438, 4); It meets your (extremely limited) criteria. Will that work for you? Otherwise how are we supposed to know what's supposed to be IN the 438 by 4 array? |