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From: Courtney on 19 Apr 2010 16:27 Hi all, I am trying to find a way to write the following formula in Excel 2003. I have tried SUMPRODUCT but it does not seem to work when both criteria have text values. I tried COUNTIF & COUNTIF but I think the wildcard * is throwing off the result. =COUNTIFS('Cycle 1'!$B$14:$B$1069, "Auto*", 'Cycle 1'!$J$14:$J$1069, "100%") Please help! Thank you! url:http://www.ureader.com/gp/1042-1.aspx
From: T. Valko on 19 Apr 2010 16:54 >COUNTIFS('Cycle 1'!$B$14:$B$1069, "Auto*", 'Cycle 1'!$J$14:$J$1069, "100%") Does the range J14:J1069 contain numbers formatted as Percentage? See if this does what you want... =SUMPRODUCT(--(LEFT('Cycle 1'!$B$14:$B$1069,4)="Auto"),--('Cycle 1'!$J$14:$J$1069=1)) -- Biff Microsoft Excel MVP "Courtney" <cprince(a)fficNOSPAM.com> wrote in message news:d642c5f5ecd941329fa755e81e2806c4(a)newspe.com... > Hi all, > > I am trying to find a way to write the following formula in Excel 2003. I > have tried SUMPRODUCT but it does not seem to work when both criteria have > text values. I tried COUNTIF & COUNTIF but I think the wildcard * is > throwing off the result. > > =COUNTIFS('Cycle 1'!$B$14:$B$1069, "Auto*", 'Cycle 1'!$J$14:$J$1069, > "100%") > > > Please help! > Thank you! > > url:http://www.ureader.com/gp/1042-1.aspx
From: Courtney on 19 Apr 2010 19:24 Hi thanks for your quick response. I'm getting a "#DIV/0" error. Soemthing must be wrong because when I use COUNTIFS in 2007, the result is 26. Any ideas of what could be causing this error or what could fix the formula? url:http://www.ureader.com/msg/104258258.aspx
From: T. Valko on 19 Apr 2010 22:01 >I'm getting a "#DIV/0" error. Do you have #DIV/0! errors in any of the referenced ranges? Try this array formula** : =SUM(IF(LEFT('Cycle 1'!B14:B1069,4)="Auto",IF(ISNUMBER('Cycle 1'!J14:J1069),IF('Cycle 1'!J14:J1069=1,1)))) ** array formulas need to be entered using the key combination of CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT key then hit ENTER. -- Biff Microsoft Excel MVP "Courtney" <cprince(a)fficNOSPAM.com> wrote in message news:a80e6bd35df341b69b48fb41633d10e0(a)newspe.com... > Hi thanks for your quick response. I'm getting a "#DIV/0" error. > Soemthing > must be wrong because when I use COUNTIFS in 2007, the result is 26. Any > ideas of what could be causing this error or what could fix the formula? > > url:http://www.ureader.com/msg/104258258.aspx
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