From: Franziska Neugebauer on
mueckenh(a)rz.fh-augsburg.de wrote:

> Carsten Schultz schrieb:
>> > You assume that the union P_i of paths contains more paths than can
>> > be constructed from finite initial segments?
>>
>> I do not assume anything. I just note that being a path in the union
>> of the T_i and being an element of the union of the P_i are a priori
>> different things and that you would have to prove their equivalence
>> in your setting should you claim this equivalence.
>
> The union of all finite trees is an infinite tree.

Definition of union of all finite trees and if necessary proof of
existence?

F. N.
--
xyz
From: Andy Smith on
mueckenh(a)rz.fh-augsburg.de writes
>
>Andy Smith schrieb:
>
>> I
>> > > > > The union of all finite binary trees contains all levels
>> > > > >which can be
>> > > > > enumerated by natural numbers:
>> > > > >
>> > > > > 0 0.
>> > > > > / \
>> > > > > 1 0 1
>> > > > > / \ / \
>> > > > > 2 0 1 0 1
>> > > > > ...............................
>> > > > >
>>
>> Out of interest, aren't the set of all numbers defined by the union of
>> all paths through a finite binary tree with N levels just all the
>> numbers addressed by the first N bits? If so, why do you bother with
>> the tree construction - does it have some special significance?
>
>The real numbers are represented as infinite paths in the "complete"
>infinite tree. Some even twice.
>
>The union of all finite trees is an infinite tree.
>Every finite tree contains only a finite set of paths.
>The countable union of all paths of the finite trees is therefore the
>countable union of all finite paths.
>The countable union of all finite paths is in the union of all finite
>trees.
>The "complete" tree containing all paths is identical to the union of
>al finite trees, with respect to nodes and edges.
>Identical trees cannot contain different sets of paths.
>Therefore, both trees contain the same set of paths.
>Therefore the "complete" set of all path is countable.
>Therefore the set of all real numbers is countable.
>Therefore ZFC is inconsistent.

I would have said that the set of all paths in a finite tree of depth N
correspond 1:1 with the address range of N bits.

An infinite tree corresponds to a number encoded in a countably infinite
set of bits.

Cantor's diagonalisation argument then applies. But, I think that there
are other reasons for thinking that the reals are uncountable anyway.

But I am not qualified to comment anyway.

Regards
--
Andy Smith

From: David Marcus on
Andy Smith wrote:
> mueckenh(a)rz.fh-augsburg.de writes
> >
> >Andy Smith schrieb:
> >
> >> I
> >> > > > > The union of all finite binary trees contains all levels
> >> > > > >which can be
> >> > > > > enumerated by natural numbers:
> >> > > > >
> >> > > > > 0 0.
> >> > > > > / \
> >> > > > > 1 0 1
> >> > > > > / \ / \
> >> > > > > 2 0 1 0 1
> >> > > > > ...............................
> >> > > > >
> >>
> >> Out of interest, aren't the set of all numbers defined by the union of
> >> all paths through a finite binary tree with N levels just all the
> >> numbers addressed by the first N bits? If so, why do you bother with
> >> the tree construction - does it have some special significance?
> >
> >The real numbers are represented as infinite paths in the "complete"
> >infinite tree. Some even twice.
> >
> >The union of all finite trees is an infinite tree.
> >Every finite tree contains only a finite set of paths.
> >The countable union of all paths of the finite trees is therefore the
> >countable union of all finite paths.
> >The countable union of all finite paths is in the union of all finite
> >trees.
> >The "complete" tree containing all paths is identical to the union of
> >al finite trees, with respect to nodes and edges.
> >Identical trees cannot contain different sets of paths.
> >Therefore, both trees contain the same set of paths.
> >Therefore the "complete" set of all path is countable.
> >Therefore the set of all real numbers is countable.
> >Therefore ZFC is inconsistent.
>
> I would have said that the set of all paths in a finite tree of depth N
> correspond 1:1 with the address range of N bits.
>
> An infinite tree corresponds to a number encoded in a countably infinite
> set of bits.
>
> Cantor's diagonalisation argument then applies. But, I think that there
> are other reasons for thinking that the reals are uncountable anyway.

The diagonal argument is sufficient. But, there are other proofs.

> But I am not qualified to comment anyway.

You are more qualified than is WM.

--
David Marcus
From: MoeBlee on
Han de Bruijn wrote:
> MoeBlee wrote:
>
> > [ ... ] And meanwhile, I always have my ears open for ideas not in
> > the mainstream, including intuitionism, finitism, ultra-finitism,
> > non-standard logics, paraconsistent logic, as well as the many
> > philosophical approaches such as constructivism, realism,
> > structuralism, fictionalism, and even as farflung as certain mystical
> > views of logic and mathematics. (But that doesn't entail that I don't
> > also exercise my prerogative to skewer postings by cranks.)
>
> How about materialism, engineering, applications, numerical analysis,
> computer graphics? You have't seen anything of the latter kind, huh?

There's nothing I wouldn't like to know more about. I do tend to prefer
purely abstract mathematics to applied mathematics, though that is not
a philosophical position so much as just a personal inclination. This
subject is but a hobby for me, and I am not even talented in the
subject, so, alas, my finite time and intellect prevent me from knowing
about everything all at once, even as much as I would like to.

> > I haven't found your questions to be stupid. But I do think your
> > questions would benefit by being put in the light of mathematical
> > definitions and some familiarity with certain basics of the subject.
>
> Especially the "light" is what bothers some of us ..

A stunning rejoinder you have posted.

MoeBlee

From: Virgil on
In article <36389$45af2b2f$82a1e228$19589(a)news1.tudelft.nl>,
Han de Bruijn <Han.deBruijn(a)DTO.TUDelft.NL> wrote:

> MoeBlee wrote:
>
> > [ ... ] And meanwhile, I always have my ears open for ideas not in
> > the mainstream, including intuitionism, finitism, ultra-finitism,
> > non-standard logics, paraconsistent logic, as well as the many
> > philosophical approaches such as constructivism, realism,
> > structuralism, fictionalism, and even as farflung as certain mystical
> > views of logic and mathematics. (But that doesn't entail that I don't
> > also exercise my prerogative to skewer postings by cranks.)
>
> How about materialism, engineering, applications, numerical analysis,
> computer graphics? You have't seen anything of the latter kind, huh?
>
> > I haven't found your questions to be stupid. But I do think your
> > questions would benefit by being put in the light of mathematical
> > definitions and some familiarity with certain basics of the subject.
>
> Especially the "light" is what bothers some of us ..
>
> Han de Bruijn

We have noticed that you perfer darkeness.