From: William Hughes on

mueckenh(a)rz.fh-augsburg.de wrote:
> Dik T. Winter schrieb:
>
> > In article <1162820871.886446.129490(a)k70g2000cwa.googlegroups.com> mueckenh(a)rz.fh-augsburg.de writes:
> > > Dik T. Winter schrieb:
> > > > In article <1162557178.206693.187650(a)e3g2000cwe.googlegroups.com> mueckenh(a)rz.fh-augsburg.de writes:
> > ...
> > > > > I believe that a taken maximum and a not taken supremum are so
> > > > > different (although the difference is very tiny) that set theory,
> > > > > necessarily assuming this, is wrong.
> > > >
> > > > There is not a taken maximum.
> > >
> > > Oh no? The lengths of the columns of the list
> > >
> > > 0.1
> > > 0.11
> > > 0.111
> > > ...
> > >
> > > are not omega? I was under the impression that there are aleph_0 lines
> > > with less than aleph_0 columns.
> >
> > There are alpeh_0 lines and aleph_0 columns. But neither is a maximum.
> > Both are supprema. There is no aleph_0-th line as there is no
> > aleph_0-th column. So, where is there a maximum involved?
>
> There is the following difference:
> The first and (any other) column has actually aleph_0 1's.
> No line has aleph_0 1's.
> So the first column is the maximum which is not reached by the lines.
> >
> > > > > The difference between maximum und supremum is, by the way, the reason
> > > > > why I insist that an actually infinite set of natural numbers must
> > > > > contain a non-natural number.
> > > >
> > > > Yes, you keep insisting that, but as there is no maximum, that insistance
> > > > is futile.
> > >
> > > The number 0.111... or the diagonal has alep_0 1's as has the n-th
> > > column but there i sno line having aleph_0 1's.
> >
> > Yes. What does that prove? *Not* that the infinite set of natural numbers
> > contains a non-natural number. Because that is obviously nonsense.
>
> And this obvious nonsense results from the assumption that the set N
> does exist.
> >
> > > > But let's take the actually infinite set of natural numbers.
> > > > Suppose it contains your non-natural number. Now remove that non-natural
> > > > number from that set. Isn't the set still actually infinite?
> > >
> > > That shows only the self-contradiction of the notion actual infinity.
> >
> > No self-contradiction at all. What *is* the self contradiction?
>
> It is the set which is equinumerous with the 1's in the column, but not
> with the 1's in any line.
> >
> > > > What you are confused about is that the cardinality (and ordinality) of
> > > > the set of natural number is indeed actually infinite; but the *contents*
> > > > are only potentially infinite.
> > >
> > > You see not difference between the infinite man 1's of 0.111... and the
> > > finite many 1's in every line?
> >
> > I see a difference, but I have no problem with that difference.
>
> The problem is that the bijection n <--> n fails. There are n numbers
> in the set {1,2,3,...,n}
>
> 1 1
> 2 1,2
> 3 1,2,3
> ... ...
> n 1,2,3,...,n
> ... ...
> omega 1,2,3,...
> omega + 1 1,2,3,...,omega
> ... ...
> omega + n 1,2,3,...,omega + n + 1
>
> >
> > > > > > > you remember? Without an infinite number in the list there is no
> > > > > > > infinite diagonal defined.
> > > > > >
> > > > > > I state (you know that) that the diagonal: 0.111...
> > > > >
> > > > > Yes, again mixing up maximum and supremum.
> > > >
> > > > No, not mixing at all. Supremum only.
> > >
> > > Then 0.111... is not different from the finite sequences of 1's?
> >
> > How do you conclude that? Given finite initial segments of the triangle
> > we get a length, a width and a length of the diagonal that are all equal.
> > When we look at the complete triangle (which exists by the axiom of
> > infinity) all three become the supremum of the finite quantities, and
> > so still are equal. No maximum involved.
> >
> The diagonal and the left side of triangle are complete with infinitely
> many ones, but no line has infinitely many 1's.
>
> > > > > But the length is realized as a whole number by a set of elements
> > > > > (lines) while the width is not realized by a set of columns.
> > > >
> > > > You are confused between two concepts. The length is not realised in the
> > > > sense you think it is.
> > >
> > > The length every column is infinite and larger than any n while no line
> > > is.
> >
> > Yes. What is the problem with that? The length is realised as omega as
> > the supremum of all finite lengths, so is the width realised as omega as
> > the supremum of all finite widths. Where is the difference?
>
> The length is not only a supremum but exists as a maximum (if all
> natural numbers exist).
>

No.

Consider the two sets.

A={1,2,3,...}
B = {1,2,3,...,omega}

Both sets have omega as supremum. Set A does not contain its supremum,
set B
does. In the first case the supremem is not a maximum, in the second
case
it is. So it is not true that the supremum must also be a maximum.


- William Hughes

From: mueckenh on
David Marcus schrieb:

> mueckenh(a)rz.fh-augsburg.de wrote:
> >
> > David Marcus schrieb:
> >
> > > mueckenh(a)rz.fh-augsburg.de wrote:
> > > > David Marcus schrieb:
> > >
> > > > > Modern mathematics does not use the term "finished infinity". If you
> > > > > wish to use it, please define it.
> > > >
> > > > Modern mathematics assumes that there are sets which are larger than
> > > > infinite sets. That is the same as to say after one finished infinity
> > > > we consider the next infinity.
> > >
> > > I asked you for a definition of "finished infinity". Is what you wrote
> > > supposed to be the definition? Normally, a definition should start out
> > > something like "Finished infinity is ... ".
> >
> > It is tedious to explain things to you.
>
> How would you know, since you never explain anything you say?

I do explain. But a certain basic vocabulary is necessary to
understand.
>
> > Please consult a book. Hint:
> > "Some mathematicians object to the Axiom of Infinity on the grounds
> > that a collection of objects produced by an infinite process (such as
> > N) should not be treated as a finished entity." (Karel Hrbacek and
> > Thomas Jech: "Introduction to set theory" Marcel Dekker Inc., New York,
> > 1984, 2nd edition.)
> >
> > Now substitute "entity" by the most significant property of the set N.
>
> So, "finished infinity" isn't even in the book you reference. Kind of
> silly for you to refer us to a book to look up what a phrase means when
> the book doesn't even use it.

Do you always repeat only full sentences you read in a book?
Did you never try to learn substituting words in sentences?

If 2 + 3 = x you can be sure that x + 5 = 10, even if that is not
written down in a book. Now apply this to "finished entity" and "a
collection of objects produced by an infinite process"

Regards, WM

From: mueckenh on

Virgil schrieb:


> Every part of the discussion is crystal clear except for WM's
> maunderings which seem more and more to be deliberately obfuscating.
>
> If every line is finite, say, for example, the nth line is of length
> 2*n, and the diagonal is not finite , then the diagonal MUST be longer
> that every line.

By definition the diagonal of a matrix cannot be longer than every line
of the matrix.
Considering your reaction to the vase, I guess you would even accept a
circle the diameter of which is longer than its circumference. Please
let us stop here. I see no point in explaining to you any logical
truth. It is useless to continue this discussion.

Regards, WM

From: mueckenh on

Virgil schrieb:

> > > That's a wrong definition of the word "definition", at least in
> > > Mathematics.
> >
> > As you believe?
>
> As mathematicians believe. A definition, at least in the mathematical
> sense, is merely a form of abbreviation. It allows one to say more
> briefly what could be said without it but at greater length.

Correct. An expression, a long one or a short one, is explained in
other words, more briefly or more detailled, respectively.

> >
> > > > Would you understand: "The new number omega is the limit to which the
> > > > (natural) numbers n grow"? Or is even hat too incomprehensible to you,
> > > > because you don't know the meanings of "number", "limit", and "grow"?
>
> Which natural number(s) does WM suggest grows?

I do not suggest anything here. This is a sentence by Cantor.

Regards, WM

From: mueckenh on

Virgil schrieb:

> What I claim is that there is a line for every MEMBER of N (or omega).
> and if each line numbered n has at least n entries, there is a column
> for each member of N ( or omega).
> I do not say that the "number" of either is "equal" to omega, as I do
> not know what that means unless it means no more than what I said above
> that there is a member for each member of omega.

But you think that there are *all* members of omega. And you think that
their number is omega.
>
> > It contradicts the square matrix which is required for Cantor's
> > diagonal argument.
>
> I do not recall anything in the Cantor proof about square matrices.
>
> The only requirement in the Cantor "diagonal" proof is that the nth
> number listed have a determinable nth decimal digit.
>
> And that does not require any sort of "square matrix".

This condition describes a square matrix (if actual infinity is a
number). For every number there is a corresponding digit and for every
digit there is a corresponding number. And there is a numbers which
counts all the numbers and digits.

Regards, WM