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From: Joubert on 26 Jun 2010 05:53 y'=(y^2 - 1)(y^2 + x^2) y(0)=y* Prove that there is a unique maximal solution. Prove that if y* > 1 there is not a globally defined solution (as opposed to when |y*| < 1). How can I prove it? Thanks.
From: Rob Johnson on 26 Jun 2010 07:07 In article <4c25ce14$0$12125$4fafbaef(a)reader4.news.tin.it>, Joubert <waterhemlock8985(a)gmail.com> wrote: >y'=(y^2 - 1)(y^2 + x^2) >y(0)=y* > >Prove that there is a unique maximal solution. >Prove that if y* > 1 there is not a globally defined solution (as >opposed to when |y*| < 1). How can I prove it? You have guile but no patience. You've gotten more than enough help in another thread. <http://groups.google.com/group/sci.math/browse_frm/thread/73915aa1aa45d121> Rob Johnson <rob(a)trash.whim.org> take out the trash before replying to view any ASCII art, display article in a monospaced font
From: Joubert on 26 Jun 2010 09:33
> You have guile but no patience. You've gotten more than enough help > in another thread. Yup sorry. Just saw it. |