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From: supergems on 8 Jun 2010 08:44 Read this discussion: http://groups.google.com/group/comp.sys.hp48/browse_thread/thread/3da4c3b04a0ee61a and remember that 'lim(F(Z),ABS(Z)=\oo)' = 'lim(F(1/Z),ABS(Z)=0)' ;-)
From: Virgil on 9 Jun 2010 01:01 In article <87eigh695s.fsf(a)merciadriluca-station.MERCIADRILUCA>, Merciadri Luca <Luca.Merciadri(a)student.ulg.ac.be> wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > Virgil <Virgil(a)home.esc> writes: > > > In article <87typf11fa.fsf(a)merciadriluca-station.MERCIADRILUCA>, > > Merciadri Luca <Luca.Merciadri(a)student.ulg.ac.be> wrote: > > > >> -----BEGIN PGP SIGNED MESSAGE----- > >> Hash: SHA1 > >> > >> Virgil <Virgil(a)home.esc> writes: > >> > >> > In article <87k4qcb9cx.fsf(a)merciadriluca-station.MERCIADRILUCA>, > >> > Merciadri Luca <Luca.Merciadri(a)student.ulg.ac.be> wrote: > >> > > >> >> -----BEGIN PGP SIGNED MESSAGE----- > >> >> Hash: SHA1 > >> >> > >> >> Hi, > >> >> > >> >> One can define sin(z), z being a complex number. How can the HP50g > >> >> compute the limit of sin(z) when z approaches the positive infinity? > >> > > >> > Along what path? > >> > > >> > As far as I can see, there is no Z path towards positive real infinity > >> > along which SIN(Z) would even have a limit. > >> Sorry, I forgot to mention that this is not z, but |z|, and for > >> |(sin(z))/[(z^2 + a^2)^2]|. But if I > >> take a correct limit (i.e. one which exists), how can I compute it > >> with the 50g? > >> > > >> >> (I.e. what could I type to achieve this?) I can evidently compute > >> >> limits for real-valued functions, with the HP50g, but I never tried > >> >> (and I don't know how to do it) with complex functions. > > > > If the limit exists at all, it will exist along every complex path from > > z = 0 to |z| = oo. > > > > So to start with try it along each of the paths from 0 towards oo along > > one of the axial directions of the complex plane: > > t, -t, i*t and -i*t as real t goes towards oo. > > For each of those, you can work out explicit real expressions for > > |(sin(z))/[(z^2 + a^2)^2]| > > > > If all 4 have limits and are equal then there may actually be a limit > > for arbitrary paths > Yes, but I thought that the HP50g could have been able to try for all > the axial directions of C^2! It can, but only one at a time.
From: Merciadri Luca on 9 Jun 2010 16:41
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Thanks all. - -- Merciadri Luca See http://www.student.montefiore.ulg.ac.be/~merciadri/ - -- Don't judge a man by the size of his hat, but by the angle of his tilt. -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.9 (GNU/Linux) Comment: Processed by Mailcrypt 3.5.8 <http://mailcrypt.sourceforge.net/> iEYEARECAAYFAkwP/JQACgkQM0LLzLt8MhzUgwCfZCeZaM2NV3eAP/JN9pukSCn+ lK8Anichyb9fFUXiVcuZS3jbnqCQTiax =5mAw -----END PGP SIGNATURE----- |