From: TonyAntique on 27 Mar 2010 15:51 How do I activate a command button on the main form when I double click on the sub form?
From: Allen Browne on 27 Mar 2010 21:33 "TonyAntique" <u59027(a)uwe> wrote in message news:a5a6118d13dbf(a)uwe... > How do I activate a command button on the main form when I double click > on the sub form? The code would be like this: Me.Parent!Command99.Enabled = True But you'll need to define "double-click on the subform" more precisely. It's probably the dblClick event of the subform's Detail section you want to use. -- Allen Browne - Microsoft MVP. Perth, Western Australia Tips for Access users - http://allenbrowne.com/tips.html Reply to group, rather than allenbrowne at mvps dot org.
From: TonyAntique via AccessMonster.com on 28 Mar 2010 14:09 Allen many thanks. I am sorry I wasn't precise enough . Me.Parent!Command99.Enabled = True will make it active or not (True or False) but I wanted to trigger the command button from the sub form. Me.Parent!Command99_Click causes Run-time error'438' not supported. I'm sure the answer is simple but I just can't find it! Allen Browne wrote: >> How do I activate a command button on the main form when I double click >> on the sub form? > >The code would be like this: > Me.Parent!Command99.Enabled = True > >But you'll need to define "double-click on the subform" more precisely. It's >probably the dblClick event of the subform's Detail section you want to use. > -- Message posted via http://www.accessmonster.com
From: Douglas J. Steele on 28 Mar 2010 15:46 Allen told you how to enable a command button on the parent form, not how to run the code associated with the button's Click event. To have it call the code, you'd need Call Me.Parent.Command99_Click Note that you'll need to change the declaration for Command99_Click from Private Sub Command99_Click() to Public Sub Command99_Click() Incidentally, do yourself a HUGE favour, and start renaming your controls so that they're more meaningful. -- Doug Steele, Microsoft Access MVP http://I.Am/DougSteele (no private e-mails, please) "TonyAntique via AccessMonster.com" <u59027(a)uwe> wrote in message news:a5b1c09b9617b(a)uwe... > Allen many thanks. > I am sorry I wasn't precise enough . > Me.Parent!Command99.Enabled = True will make it active or not (True or > False) > but I wanted to trigger the command button from the sub form. > Me.Parent!Command99_Click causes Run-time error'438' not supported. > > I'm sure the answer is simple but I just can't find it! > > Allen Browne wrote: >>> How do I activate a command button on the main form when I double click >>> on the sub form? >> >>The code would be like this: >> Me.Parent!Command99.Enabled = True >> >>But you'll need to define "double-click on the subform" more precisely. >>It's >>probably the dblClick event of the subform's Detail section you want to >>use. >> > > -- > Message posted via http://www.accessmonster.com >
From: TonyAntique via AccessMonster.com on 28 Mar 2010 16:59 Thanks Douglas J. Steele wrote: >Allen told you how to enable a command button on the parent form, not how to >run the code associated with the button's Click event. > >To have it call the code, you'd need > > Call Me.Parent.Command99_Click > >Note that you'll need to change the declaration for Command99_Click from > >Private Sub Command99_Click() > >to > >Public Sub Command99_Click() > >Incidentally, do yourself a HUGE favour, and start renaming your controls so >that they're more meaningful. > >> Allen many thanks. >> I am sorry I wasn't precise enough . >[quoted text clipped - 15 lines] >>>probably the dblClick event of the subform's Detail section you want to >>>use. -- Message posted via AccessMonster.com http://www.accessmonster.com/Uwe/Forums.aspx/access-forms/201003/1
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