Cos infinite series
in [Matlab]
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From: Walter Roberson on 21 Mar 2010 21:55 Brittany Morgante wrote: > n=1; > % x=1 > cosval=1; > for i=1:1:n > cosval=((-1^n)*x^(2*n))/(factorial(2*n)) %formula found through google > % cosval=cosval-(-1^(i+1)/factorial(2*n)) %formula made up using > original formula on hw paper > end Biggest mistake in the new version: you are not summing the values. Each loop iteration is going to overwrite the value from the previous loop. This is in addition to the other poster who pointed out that your confusion about i and n.
From: Brittany Morgante on 21 Mar 2010 22:21 Walter Roberson <roberson(a)hushmail.com> wrote in message <ho6imr$3n1$1(a)canopus.cc.umanitoba.ca>... > Brittany Morgante wrote: > > > n=1; > > % x=1 > > cosval=1; > > for i=1:1:n > > cosval=((-1^n)*x^(2*n))/(factorial(2*n)) %formula found through google > > % cosval=cosval-(-1^(i+1)/factorial(2*n)) %formula made up using > > original formula on hw paper > > end > > Biggest mistake in the new version: you are not summing the values. Each > loop iteration is going to overwrite the value from the previous loop. > > This is in addition to the other poster who pointed out that your > confusion about i and n. with using only one of the formulas, how do you tell matlab to sum the values instead of only getting individual values for each term? i havent been using the "newest" version of matlab, but the r2008a version because that is what the school that i am going to provides on all the computers. x=1; cosval=1; for i=1:1:n cosval=((-1^i)*x^(2*i))/(factorial(2*i)) end
From: Walter Roberson on 21 Mar 2010 22:47
Brittany Morgante wrote: > with using only one of the formulas, how do you tell matlab to sum the > values instead of only getting individual values for each term? total = 0 for IndexName = 1:FinalIndex ThisValue = SomeExpressionInvolving_IndexName total = total + ThisValue end |