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From: Rob Biedenharn on 20 Jul 2010 11:05
On Jul 20, 2010, at 10:58 AM, Vitaliy Yanchuk wrote:
> Jean-Julien Fleck wrote:
>> 2010/7/20 Vitaliy Yanchuk <fuksito(a)gmail.com>:
>>> Jean-Julien Fleck, thanks.
>>> Maybe have an idea of a one-line version? :)
>>
>> Well: quite the same using inject:
>>
>> arr.inject(Hash.new(0)) {|h,e| h[e]+= 1; h}
>>
>> It all depends on what you call 'one-line' :o)
>>
>> Cheers,
>
> Wow, Inject is cool method, thanks !
> In my mind one-line is that dows not have semi-coloms or new lines of
> course
> --


Soo... that has a semi-colon and isn't then a one-liner?? ;-)

-Rob

Rob Biedenharn
Rob(a)AgileConsultingLLC.com http://AgileConsultingLLC.com/
rab(a)GaslightSoftware.com http://GaslightSoftware.com/


From: Vitaliy Yanchuk on 20 Jul 2010 11:08
Rob Biedenharn wrote:
> Soo... that has a semi-colon and isn't then a one-liner?? ;-)

Yeah, not perfectly one-liner. But it is without dot-chain breaking, not
bad too :)
--
Posted via http://www.ruby-forum.com/.

From: Joseph E. Savard on 20 Jul 2010 11:16
h = Hash.new(0)
["a", "b", "a", "c", "c", "b", "b"].each {|s| h[s] += 1};

> From: Vitaliy Yanchuk <fuksito(a)gmail.com>
> Reply-To: <ruby-talk(a)ruby-lang.org>
> Newsgroups: comp.lang.ruby
> Date: Tue, 20 Jul 2010 22:47:27 +0900
> To: ruby-talk ML <ruby-talk(a)ruby-lang.org>
> Subject: Count occurences of vars in array
>
> Hello, everyone.
>
> Would be grateful if someone can tell, how can I do shortly (mb with one
> method) from such example array
>
> ["a", "b", "a", "c", "c", "b", "b"]
>
> The result
> a => 2
> b => 3
> c => 2
>
> So, to count number of occurances
> --
> Posted via http://www.ruby-forum.com/.
>


From: Joseph E. Savard on 20 Jul 2010 11:19
Nice!

> arr.inject(Hash.new(0)) {|h,e| h[e]+= 1; h}

> --
> JJ Fleck
> PCSI1 Lycée Kléber
>


From: Jean-Julien Fleck on 20 Jul 2010 11:21
2010/7/20 Vitaliy Yanchuk <fuksito(a)gmail.com>:
> Rob Biedenharn wrote:
>> Soo... that has a semi-colon and isn't then a one-liner?? ;-)
>
> Yeah, not perfectly one-liner. But it is without dot-chain breaking, not
> bad too :)

That would be a real one-liner if I could recall how to convert
elegantly an array of size2 arrays into an hash:

arr.group_by {|o| o}.collect{|k,v| [k,v.size]}

Cheers,

--
JJ Fleck
PCSI1 Lycée Kléber

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