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From: External Update on 17 May 2010 10:45 I am having problems getting the syntax correct for the DateDiff function. Help states that it's DateDiff (interval,date1,date2). If I want the resulting interval in days, what do I enter? Thanks
From: Barbara Henhapl on 17 May 2010 11:05 Hi, use 'd' for days. Hope that helps? Regards Barbara "External Update" <ExternalUpdate(a)discussions.microsoft.com> schrieb im Newsbeitrag news:2BF18F0F-589C-4502-83D1-D18AC40AE47B(a)microsoft.com... >I am having problems getting the syntax correct for the DateDiff function. > Help states that it's DateDiff (interval,date1,date2). If I want the > resulting interval in days, what do I enter? > > Thanks
From: Andrew Lavinsky on 17 May 2010 11:15 You could also try the following syntax: ProjDateDiff([Date1],[Date2]) ....and make sure you're using a Duration field, not a number field. If you use a number field, you'll have to divide by [minutes per day] - Andrew Lavinsky Blog: http://blogs.catapultsystems.com/epm > Hi, > use 'd' for days. Hope that helps? > Regards > Barbara > "External Update" <ExternalUpdate(a)discussions.microsoft.com> schrieb > im Newsbeitrag > news:2BF18F0F-589C-4502-83D1-D18AC40AE47B(a)microsoft.com... > >> I am having problems getting the syntax correct for the DateDiff >> function. Help states that it's DateDiff (interval,date1,date2). If I >> want the resulting interval in days, what do I enter? >> >> Thanks >>
From: Dale Howard [MVP] on 17 May 2010 11:53 External Update -- To add to the excellent answers given already by several other users, I personally like the ProjDateDiff function, as it allows you to specify which calendar to use to calculate the date difference. Remember to use a custom Duration field, such as the Duration1 field, with a formula that utilizes the ProjDateDiff function. Hope this helps. -- Dale A. Howard [MVP] VP of Educational Services msProjectExperts http://www.msprojectexperts.com http://www.projectserverexperts.com "We write the books on Project Server" "External Update" <ExternalUpdate(a)discussions.microsoft.com> wrote in message news:2BF18F0F-589C-4502-83D1-D18AC40AE47B(a)microsoft.com... > I am having problems getting the syntax correct for the DateDiff function. > Help states that it's DateDiff (interval,date1,date2). If I want the > resulting interval in days, what do I enter? > > Thanks
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