From: Henry Wilson DSc on
On Tue, 02 Feb 2010 22:12:34 +0000, tominlaguna(a)yahoo.com wrote:

>On Tue, 02 Feb 2010 04:17:12 GMT, ..@..(Henry Wilson DSc) wrote:
>
>>On Mon, 1 Feb 2010 19:23:37 -0800 (PST), artful <artful_me(a)hotmail.com> wrote:
>>
>>>On Feb 2, 2:02�pm, ..@..(Henry Wilson DSc) wrote:
>>>> On Mon, 1 Feb 2010 17:00:50 -0800 (PST), PD <thedraperfam...(a)gmail.com> wrote:
>>>> >On Feb 1, 5:59�pm, train <gehan.ameresek...(a)gmail.com> wrote:
>>
>>>> >This is not what the principle of equivalence says. The principle of
>>>> >equivalence makes NO claim that the "results" will be the same in
>>>> >different inertial frames. This is KNOWN not to be true from the days
>>>> >of Galileo. A ball falling from the top of the mast on a ship takes a
>>>> >straight line path in the frame of a ship, but a parabolic path in the
>>>> >frame of the shore -- two different "results" regarding the same
>>>> >events as seen in two different frames. What the principle of
>>>> >equivalence says is that the laws of physics are the same in all
>>>> >inertial frames -- and a parabolic path and a straight line path are
>>>> >both described by the very same laws of physics.
>>>> ...but you still can't provide a logical physical reason as to why a light
>>>> pulse should reflect at the same speed from two relatively moving mirrors.
>>>>
>>>> Henry Wilson...
>>>>
>>>> .......provider of free physics lessons
>>>
>>>The incident speed wrt the mirror is the same as the reflected speed
>>>wrt the mirror. That is how mirrors work. Do you have a problem with
>>>that?
>>
>>I don't...but Einstein obviously did.
>>
>>S-----p->c(wrt source)--------------|M1
>> |M2 v<-
>>
>>Let the pulse strike the two mirrors when they are adjacent.
>>It closes on M1 at c and departs at c.
>>It closes on M2 at c+v and departs at c-v.
>>Strange, eh?
>>
>>I wonder how many fairies can dance on the surface of a mirror.
>>
>>>Then use velocity composition to work out how that speed will
>>>be in another relatively moving inertial frame. Use vector addition /
>>>subtraction to work out closing/separation speeds
>>
>>Hahahahhaaha! What kind of answer is this?
>>
>>Einstein's velocity composition equation is just another form of his P2.
>>Look, I'll show you...
>>
>>Let w (the light speed in a frame moving at v) always be = c by postulate.
>>
>>w = c = c(c+v)/(c+v) = (c+v)/(1+v/c) = (c+v)/(1+vc/c^2)
>>
>
>Great job on the equation, Henry! Keep it up.

Thanks. But I'll let Einstein have all the credit...

>>...can I have my Nobel now please...for being expert at sniffing out circular
>>logic?
>>
>>
>>
>>Henry Wilson...
>>
>>.......provider of free physics lessons


Henry Wilson...

........provider of free physics lessons
From: PD on
On Feb 2, 2:21 pm, John Kennaugh <J...(a)notworking.freeserve.co.uk>
wrote:
> PD wrote:
> >On Jan 31, 1:23 pm, Bruce Richmond <bsr3...(a)my-deja.com> wrote:
>
> >> De Sitter's argument supports many theories that consider the speed of
> >> light to be source independent.  Other experiments eliminate most of
> >> them.  To eliminate a theory you need to come up with an experiment
> >> that contradicts a prediction of the theory.  Since SR and LET share
> >> the same math you can't eliminate one without also eliminating the
> >> other.
>
> >This isn't quite so. SR makes predictions that LET does not, and
> >that's because the *physical* foundations are different, though the
> >math is common in their *common* experimental domain.
>
> What a load of waffle.
> SR does not have any *physical* foundations it is a principle theory; a
> mathematical model based on "empirical foundations" (AE). It is based
> upon two postulates the first was thought not to apply to EM theory as
> it was believed that every FoR was unique in that it had a unique speed
> w.r.t Maxwell's aether. That was shown not to be the case as the sort of
> experiment expected to show absolute speed dependency failed to do so.
> The PoR which has its origins with Galileo I think was therefore
> re-established empirically. The second postulate is a mixture of
>
> i) Maxwell's aether theory - which stated that the speed of light is
> independent of the speed of the source because it is constant w.r.t the
> aether.
>
> ii) The generally held view among Einstein's contemporaries was that the
> MMX had shown that an observer has always zero speed w.r.t the aether.
> The second postulate simply describes what an observer stationary w.r.t
> the aether would observe. Einstein's attempts to convince others that he
> was on to something *physical* in justification of the postulate in the
> form of "an aether without the immobility of Lorentz's" (1920 lecture)
> failed. Einstein's objection to Lorentz's theory was in respect of the
> theoretical structure i.e. its physical interpretation and he totally
> failed to come up with an alternative. Physicists decided that a physics
> theory did not require a physical interpretation and accepted SR without
> one. As the aether was part of the physical interpretation of Maxwell's
> theory this decision also allowed physics to disown the aether and
> describe a set of equations SR/Lorentz and Maxwell as a "theory".
>
> >Thus, experimental support for our model of the weak
> >interaction is also support for SR, though not for LET
> >For example, SR
> >makes the statement that ANY interaction must be manifestly covariant,
> >which includes, for example, the weak interaction. LET makes no claim
> >like that.
>
> If you are talking of the theory as provided by Einstein then his theory
> made no such claim either.

But I did not say that. I said SR, which is a *living* theory, not one
that came complete and in finished form in 1905.

> All you are saying is that such a statement
> has been added as a part of relativity but has not been added to LET. SR
> is simply Lorentz's maths without the theory which went with it.

That's incorrect. SR as it *presently* exists is a physical theory
that has a *different* physical basis than LET.

>
> >. The converse
> >is that if *any* interaction showed signs of violating covariance,
> >then SR would be in some trouble, while LET would not necessarily be
> >likewise. So the stakes are higher in that regard for SR.
>
> --
> John Kennaugh

From: Henry Wilson DSc on
On Tue, 2 Feb 2010 14:51:12 -0800 (PST), artful <artful_me(a)hotmail.com> wrote:

>On Feb 3, 7:17�am, ..@..(Henry Wilson DSc) wrote:
>> Consider a vertical mirror moving towards a light source.
>>
>> S--------------------------v<--|M
>>
>> I challenge you to apply any of Einstein's equations to show that, in the
>> mirror frame, the reflected and incident light speeds are the same.
>
>What sort of challenge is that? Pretty much trivial.
>
>SR says speed of light is c in every inertial frame .. so in frame of
>mirror, incident speed is c and reflected speed is c. c == c. Done.

Not done. You have merely restated P2.

>If you really want, you can use the velocity composition formula to
>convert the speed c in the S frame to c in the M frame. And if
>incident speed is c, reflected speed is c.

Is it?

Why don't you show me how and why, eh?

Show exactly how a closing speed of c+v and a separation speed of c-v in the
source frame can translate into both speeds equalling c in the mirror frame.
You are free to use any of Einstein's equations.



Henry Wilson...

........provider of free physics lessons
From: eric gisse on
...@..(Henry Wilson DSc) wrote:

> On Tue, 2 Feb 2010 14:51:12 -0800 (PST), artful <artful_me(a)hotmail.com>
> wrote:
>
>>On Feb 3, 7:17 am, ..@..(Henry Wilson DSc) wrote:
>>> Consider a vertical mirror moving towards a light source.
>>>
>>> S--------------------------v<--|M
>>>
>>> I challenge you to apply any of Einstein's equations to show that, in
>>> the mirror frame, the reflected and incident light speeds are the same.
>>
>>What sort of challenge is that? Pretty much trivial.
>>
>>SR says speed of light is c in every inertial frame .. so in frame of
>>mirror, incident speed is c and reflected speed is c. c == c. Done.
>
> Not done. You have merely restated P2.
>
>>If you really want, you can use the velocity composition formula to
>>convert the speed c in the S frame to c in the M frame. And if
>>incident speed is c, reflected speed is c.
>
> Is it?
>
> Why don't you show me how and why, eh?

What would be the point of that?

>
> Show exactly how a closing speed of c+v and a separation speed of c-v in
> the source frame can translate into both speeds equalling c in the mirror
> frame. You are free to use any of Einstein's equations.
>
>
>
> Henry Wilson...
>
> .......provider of free physics lessons

From: Henry Wilson DSc on
On Tue, 02 Feb 2010 15:52:11 -0800, eric gisse <jowr.pi.nospam(a)gmail.com>
wrote:

>..@..(Henry Wilson DSc) wrote:
>
>> On Tue, 2 Feb 2010 14:51:12 -0800 (PST), artful <artful_me(a)hotmail.com>
>> wrote:
>>
>>>On Feb 3, 7:17 am, ..@..(Henry Wilson DSc) wrote:
>>>> Consider a vertical mirror moving towards a light source.
>>>>
>>>> S--------------------------v<--|M
>>>>
>>>> I challenge you to apply any of Einstein's equations to show that, in
>>>> the mirror frame, the reflected and incident light speeds are the same.
>>>
>>>What sort of challenge is that? Pretty much trivial.
>>>
>>>SR says speed of light is c in every inertial frame .. so in frame of
>>>mirror, incident speed is c and reflected speed is c. c == c. Done.
>>
>> Not done. You have merely restated P2.
>>
>>>If you really want, you can use the velocity composition formula to
>>>convert the speed c in the S frame to c in the M frame. And if
>>>incident speed is c, reflected speed is c.
>>
>> Is it?
>>
>> Why don't you show me how and why, eh?
>
>What would be the point of that?

To prove that there isn't a great hole in the consistency of SR as a
mathematical theory...

>> Show exactly how a closing speed of c+v and a separation speed of c-v in
>> the source frame can translate into both speeds equalling c in the mirror
>> frame. You are free to use any of Einstein's equations.
>>
>>
>>
>> Henry Wilson...
>>
>> .......provider of free physics lessons


Henry Wilson...

........provider of free physics lessons