Decompose lParam
in [Visual Basic]
|
From: Boris Pauljev on 29 Apr 2010 12:52 Something is wrong... ' Get the keyboard scan code for "T": Dim b() As Byte b = sChar 'sChar is "T" CopyMemory vKey, b(0), 2 'vKey becomes "84" Dim iKeyCode% iKeyCode = VkKeyScanW(vKey) 'For "T", iKeyCode becomes "340" ' Split into shift and key portions: iShift = (iKeyCode And &HFF00&) \ &H100& 'iShift becomes "1" vKey = iKeyCode And &HFF& 'vKey stays "84" Const VKSHIFT = &H100 Const VKCTRL = &H200 Const VKALT = &H400 Dim bShift As Boolean Dim bAltGr As Boolean Dim bCtrl As Boolean bShift = CBool(iShift And VKSHIFT) '1 AND 256 = FALSE bCtrl = CBool(iShift And VKCTRL) '1 AND 512 = FALSE bAltGr = CBool(iShift And VKALT) '1 AND 1024 = FALSE This means that for "T" is says that no shift is being used.
From: Bob Butler on 29 Apr 2010 13:10 "Boris Pauljev" <nordiccoder(a)hotmail.com> wrote in message news:e1kS7y75KHA.1888(a)TK2MSFTNGP05.phx.gbl... > Something is wrong... > > ' Get the keyboard scan code for "T": > Dim b() As Byte > b = sChar 'sChar is "T" > CopyMemory vKey, b(0), 2 'vKey becomes "84" > > Dim iKeyCode% > iKeyCode = VkKeyScanW(vKey) 'For "T", iKeyCode becomes "340" > > ' Split into shift and key portions: > iShift = (iKeyCode And &HFF00&) \ &H100& 'iShift becomes "1" > vKey = iKeyCode And &HFF& 'vKey stays "84" > > Const VKSHIFT = &H100 > Const VKCTRL = &H200 > Const VKALT = &H400 > > Dim bShift As Boolean > Dim bAltGr As Boolean > Dim bCtrl As Boolean > > bShift = CBool(iShift And VKSHIFT) '1 AND 256 = FALSE > bCtrl = CBool(iShift And VKCTRL) '1 AND 512 = FALSE > bAltGr = CBool(iShift And VKALT) '1 AND 1024 = FALSE Sorry, I didn't copy & paste right.... the point was to avoid the bit shifting and just use the return value from vkkeyscan bShift = CBool(iKeyCode And VKSHIFT) '1 AND 256 = FALSE bCtrl = CBool(iKeyCode And VKCTRL) '1 AND 512 = FALSE bAltGr = CBool(iKeyCode And VKALT) '1 AND 1024 = FALSE
From: Bob Butler on 29 Apr 2010 13:13 "Jeff Johnson" <i.get(a)enough.spam> wrote in message news:eiZiFS75KHA.4116(a)TK2MSFTNGP02.phx.gbl... > "Bob Butler" <noway(a)nospam.ever> wrote in message > news:OmYPjG75KHA.3292(a)TK2MSFTNGP06.phx.gbl... > >> bAltGr =cbool(iShift And vkAlt) > > Just to split hairs on your naming, you don't really know it's AltGr as > opposed to just Alt. I named them based on the values defined in the docs for vkkeyscan; I don't remember offhand how to differentiate between alt and altgr. I know I've looked into it before but that was a long time ago.
From: Bob Butler on 29 Apr 2010 13:12 "Boris Pauljev" <nordiccoder(a)hotmail.com> wrote in message news:O3uDFX75KHA.5548(a)TK2MSFTNGP04.phx.gbl... > Bob, I am not sure yet, but I think your code works.... OMG, I would > really be up in the sky if this really works. I will test it on a client > computer now (who has not yet given up yet... luckily..) > > Can you explain why vbAltMask is not what I want? I mean what is it good > for if one cannot use it anyway? It's useful when you are dealing with the values in the KeyDown & KeyUp events; they are vb constants and vkkeyscan is not a VB function so there's not necessarily going to be any relationship between what it returns and what vb uses in other places.
From: Boris Pauljev on 29 Apr 2010 13:19
Thanks, but when I have vKey = 105 iKeyCode = 1605 it still tells me that Alt and Ctrl are pressed. iKeyCode comes from iKeyCode = VkKeyScanW(vKey) When the shift and alt and ctrl detecting seems to be correct, then VkKeyScanW appears to be the bad boy, right? Or does anybody disagree? |