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From: Ken S. Tucker on 11 Apr 2010 16:08
On Apr 11, 12:17 pm, "Jay R. Yablon" <jyab...(a)nycap.rr.com> wrote:
> "Mike" <mj...(a)sirus.com> wrote in message
>
> news:9266ed57-9e56-4b84-b38f-af7945eaf1b2(a)c36g2000yqm.googlegroups.com...
>
> > On Apr 11, 11:39 am, Gerard Westendorp <west...(a)xs4all.nl> wrote:
> >> I would like to make a model that contains an observer.
> >> But I can't figure out what an observer is.
> >> Does anyone have a suggestion?
>
> >> Of course, I know the *I* am an observer, and probably other humans
> >> are
> >> too. But what is the *minimum* requirement for something to be an
> >> observer?
>
> >> Gerard
>
> > I think an observer in physics is a frame of reference indicating
> > where you are in time and space, how fast you are going, how you are
> > accelerating, and what you can possibly measure.
>
> Gerard,
>
> Like Mike, I also tend to think of observer as frame of reference. But
> I extend the usual suspects mentioned by Mike to the resolution of your
> measuring instrument, i.e., how powerful is out "microscope" or whatever
> we analogize to our microscope, which is also the "probe energy" mu
> which tells us how far we penetrate the "screening" of the vacuum and
> the "dressing" of undressed particle.
>
> I am in fact in the middle of preparing a detailed forthcoming posting
> on this, for the "Planck scale physics" thread.
> Jay

I think the foundation of observation is the measurement of power.
Letting "D" stand for a finite quantity, with a lower boundary near
Plancks constant "h", then I'd define an observation as requiring
an "Occurence", that is 'occurs' within a Volume DX DY DZ in a
Time DT exchanging an Energy DE.
In that case the power (Watts) is DE/DT applied to a Volume.

A good example is photography, with an exposure of photographic
film at a certain intensity (W) inputed into a Volume, that in turn
changes the chemistry of the film,
((the bases of science and pornography)).

An oscilloscope bleeds a tiny bit of power to display a waveform,
and so does measuring airpressure in a car tire.
Regards
Ken S. Tucker





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