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From: demo on 11 Feb 2010 02:06
Given the following code, is it possible to declare an instance of bar
without explicitly specifying the Class and Type? The compiler should
know the complete type of &foo::value, so specifying the type more
than once is tedious. Could decltype or something like that be used in
C++0x?

#include "stdafx.h"

struct foo
{
int value;
};

template<typename Class, typename Type, Type Class::* Member>
struct bar
{
};

int main(int argc, char* argv[])
{
bar<foo, int, &foo::value>(); // Could this be bar<&foo::value>()
somehow?
return EXIT_SUCCESS;
}


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