From: Omega John on
Hi,

Sorry, but I am not completely following. Using your example, consider
the morphism 0 -> 0, 1 -> 2 from (1) -> (2) in Δ. Exactly which would the
associated opposite morphism (2) -> (1) be in Δ^op?

Thank you.

On Sat, 06 Feb 2010 04:23:05 -0800, victor_meldrew_666(a)yahoo.co.uk wrote:

> On 5 Feb, 20:07, Omega John <omega_john_userfrien...(a)gmail.com> wrote:
>> Hi,
>>
>> Exactly what is the difference? I know that morphisms in the former are
>> non-decreasing maps. Are the morphisms of the latter non-increasing
>> maps?
>
> No.
>
> One category is the opposite of the other. If your supposition were
> correct, then there would be as many morphisms from _m_ to _n_ in both
> categories (as there are the same number of weakly increasing maps from
> _m_ = {0,1,...,m} to _n_ as there are weakly increasing maps). But in
> the opposite to the simplex category the morphisms from _m_ to _n_
> correspond to weakly increasing maps from _n_ to _m_ and there aren't
> the same number of these as there are from _m_ to _n_ in general. For
> instance there are six weakly increasing maps from _1_ = {0,1} to _2_ =
> {0,1,2} but only for from _2_ to _1_.