From: Edward Diener on 19 Jul 2010 08:53 In Windows Vista x64 I have installed python 2.6 64-bit version and python 3.1 64-bit version to separate folders. Within the command interpreter I add python 2.6 to the PATH. In the command interpreter, When I type python somescript.py with an import sys print (sys.version) in the script, it shows: 3.1.2 (r312:79149, Mar 20 2010, 22:55:39) [MSC v.1500 64 bit (AMD64)] In the command interpreter if I type 'python' I see: Python 2.6.5 (r265:79096, Mar 19 2010, 18:02:59) [MSC v.1500 64 bit (AMD64)] on win32 Does anybody have any ideas why this is happening ?
From: Alf P. Steinbach /Usenet on 19 Jul 2010 09:15 * Edward Diener, on 19.07.2010 14:53: > In Windows Vista x64 I have installed python 2.6 64-bit version and > python 3.1 64-bit version to separate folders. Within the command > interpreter I add python 2.6 to the PATH. > > In the command interpreter, When I type python somescript.py with an > > import sys > print (sys.version) > > in the script, it shows: > > 3.1.2 (r312:79149, Mar 20 2010, 22:55:39) [MSC v.1500 64 bit (AMD64)] > > In the command interpreter if I type 'python' I see: > > Python 2.6.5 (r265:79096, Mar 19 2010, 18:02:59) [MSC v.1500 64 bit > (AMD64)] on win32 > > Does anybody have any ideas why this is happening ? At a guess your description of what's happening is not entirely accurate. Although it could be, since Windows moves in mysterious ways. Please try the following commands in sequence, with no other commands: python -V echo %path% ftype python.file python somescript.py Then right-click the command interpreter's title bar to get edit menu. /Mark/ the text of your commands and results. Then /copy/ it to the clipboard (note: you can't use [Ctrl C] here, use the edit menu or just press Enter). Then post the commands and results here, /paste/ them into your message (e.g. [Ctrl V]). And then, if you haven't already figured it out, somebody probably will. :-) Cheers & hth., - Alf -- blog at <url: http://alfps.wordpress.com>
From: Edward Diener on 19 Jul 2010 17:45 On 7/19/2010 9:15 AM, Alf P. Steinbach /Usenet wrote: > * Edward Diener, on 19.07.2010 14:53: >> In Windows Vista x64 I have installed python 2.6 64-bit version and >> python 3.1 64-bit version to separate folders. Within the command >> interpreter I add python 2.6 to the PATH. >> >> In the command interpreter, When I type python somescript.py with an >> >> import sys >> print (sys.version) >> >> in the script, it shows: >> >> 3.1.2 (r312:79149, Mar 20 2010, 22:55:39) [MSC v.1500 64 bit (AMD64)] >> >> In the command interpreter if I type 'python' I see: >> >> Python 2.6.5 (r265:79096, Mar 19 2010, 18:02:59) [MSC v.1500 64 bit >> (AMD64)] on win32 >> >> Does anybody have any ideas why this is happening ? > > At a guess your description of what's happening is not entirely accurate. > > Although it could be, since Windows moves in mysterious ways. > > Please try the following commands in sequence, with no other commands: > > python -V > echo %path% > ftype python.file > python somescript.py > > Then right-click the command interpreter's title bar to get edit menu. > /Mark/ the text of your commands and results. Then /copy/ it to the > clipboard (note: you can't use [Ctrl C] here, use the edit menu or just > press Enter). Then post the commands and results here, /paste/ them into > your message (e.g. [Ctrl V]). > > And then, if you haven't already figured it out, somebody probably will. > :-) I figured out the cause. One of the Python scripts started with: #!Path/to/Python31Executable which evidently caused python 3.1 to be called to run that script. I am not sure that script was run via an 'import' statement, as opposed to a 'python someScript.py' within another script, but I suspect the latter.
From: Edward Diener on 19 Jul 2010 21:50 On 7/19/2010 5:45 PM, Edward Diener wrote: > On 7/19/2010 9:15 AM, Alf P. Steinbach /Usenet wrote: >> * Edward Diener, on 19.07.2010 14:53: >>> In Windows Vista x64 I have installed python 2.6 64-bit version and >>> python 3.1 64-bit version to separate folders. Within the command >>> interpreter I add python 2.6 to the PATH. >>> >>> In the command interpreter, When I type python somescript.py with an >>> >>> import sys >>> print (sys.version) >>> >>> in the script, it shows: >>> >>> 3.1.2 (r312:79149, Mar 20 2010, 22:55:39) [MSC v.1500 64 bit (AMD64)] >>> >>> In the command interpreter if I type 'python' I see: >>> >>> Python 2.6.5 (r265:79096, Mar 19 2010, 18:02:59) [MSC v.1500 64 bit >>> (AMD64)] on win32 >>> >>> Does anybody have any ideas why this is happening ? >> >> At a guess your description of what's happening is not entirely accurate. >> >> Although it could be, since Windows moves in mysterious ways. >> >> Please try the following commands in sequence, with no other commands: >> >> python -V >> echo %path% >> ftype python.file >> python somescript.py >> >> Then right-click the command interpreter's title bar to get edit menu. >> /Mark/ the text of your commands and results. Then /copy/ it to the >> clipboard (note: you can't use [Ctrl C] here, use the edit menu or just >> press Enter). Then post the commands and results here, /paste/ them into >> your message (e.g. [Ctrl V]). >> >> And then, if you haven't already figured it out, somebody probably will. >> :-) > > I figured out the cause. One of the Python scripts started with: > > #!Path/to/Python31Executable > > which evidently caused python 3.1 to be called to run that script. I am > not sure that script was run via an 'import' statement, as opposed to a > 'python someScript.py' within another script, but I suspect the latter. No, this is incorrect. The cause had nothing to do with the above. It was because .py files were associated with the 3.1 version of Python, no Python folder was in the PATH, and a Pyhton script invoked python passing it a .py file. So even though the initial command specified the 2.6 version of Python on a script, subsequent scripts were run using Python 3.1. I since changed the association of .py files to the 2.6 version of Python and everything works correctly.
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