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From: Sergei on 20 Nov 2009 07:01 When talking about an indistinguishable encryption, it is required that the probabilities of distinguishing two encrypted plaintext differ negligibly. In contrast, in the definition of the differential privacy, it is required that the probabilities of getting the same results if computing a function on two data sets differing by at most one element differ by a small multiplicative factor exp^(x). The question is: Why not using a negligible function in the case for differential privacy as well? Is it because having a multiplicative factor allows to make differential privacy achievable when perturbing the data using gaussian, binomial or Laplace distribution? Or are there some fundamental reasons for it? Sergei |