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From: alainverghote on 29 Jun 2010 12:56 Good day sunshine... Building duos of squares seems easy . Since any integer factorizable into two distinct factors of same parity is equal to one (at least) difference of two squares: Ex: 105=5*21 = 7*15 = 1*105 ,we begin with two known values 4^2 + ... = 11^2+... 4^2 + 5*21 = 11^2 4^2 + (13-8)(13+8) = 11^2 4^2 + 13^2 = 11^2+8^2 ............ 4^2+53^2 = 11^2 + 52^2 This process was used in many squares Catalan equalities, Alain |