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From: Len on 5 Feb 2010 11:12 Hi, After several attempts to run the codes below, it fails to copy each row of data in column A of sheet1 from workbookX instead it copied the last row of data only ( ie only response to last row in this array "rngtrg(m)" ) In fact, my intended codes is to copy each row of data in column A of sheet1 from workbookX and place it in the array, then use each copied row from the array to search the text string from column D in sheet2 of another workbook(Y), If found, it will copy each matched row of data back to column A after the last used cells, of sheet1 in workbookX Extract of codes Dim m%, rngtrg$(), klstrw As Long Dim k As Integer klstrw = Cells(Rows.Count, "A").End(xlUp).Row For k = 1 To klstrw m = m + 1 ReDim Preserve rngtrg(1 To m) rngtrg(m) = Workbooks("X").Worksheets("Sheet1").Cells(k, 1) Next k Windows("WorkbookY.xls").Activate With Worksheets("Sheet2") Dim iLastRow As Long, i As Integer Dim iNextRow As Long iLastRow = .Cells(.Rows.Count, "D").End(xlUp).Row For i = 1 To iLastRow If .Cells(i, "D").Value = rngtrg(m) Then iNextRow = iNextRow + 1 ..Rows(i).Copy Workbooks("X").Worksheets("sheet1").Cells(iNextRow, "A").Offset(klstrw + 2, 0) End If Next i End With Any help on this problem will be much appreciated Thanks in advance Regards Len
From: JLGWhiz on 5 Feb 2010 13:46 I think you need to move this to inside your for loop. klstrw = Cells(Rows.Count, "A").End(xlUp).Row You would probably be better off just using an offset without reference to the klstrw variable since the klstrw variable is in one sheet and the destination range is in another. "Len" <ltong2000mal(a)yahoo.co.uk> wrote in message news:67e661a1-8f38-4513-9d23-3d7c66e958fd(a)k36g2000prb.googlegroups.com... > Hi, > > After several attempts to run the codes below, it fails to copy each > row of data in column A of sheet1 from workbookX instead it copied the > last row of data only ( ie only response to last row in this array > "rngtrg(m)" ) > In fact, my intended codes is to copy each row of data in column A of > sheet1 from workbookX and place it in the array, then use each copied > row from the array to search the text string from column D in sheet2 > of another workbook(Y), > If found, it will copy each matched row of data back to column A after > the last used cells, of sheet1 in workbookX > > > Extract of codes > > Dim m%, rngtrg$(), klstrw As Long > Dim k As Integer > klstrw = Cells(Rows.Count, "A").End(xlUp).Row > > For k = 1 To klstrw > m = m + 1 > ReDim Preserve rngtrg(1 To m) > rngtrg(m) = Workbooks("X").Worksheets("Sheet1").Cells(k, 1) > Next k > > Windows("WorkbookY.xls").Activate > With Worksheets("Sheet2") > Dim iLastRow As Long, i As Integer > Dim iNextRow As Long > iLastRow = .Cells(.Rows.Count, "D").End(xlUp).Row > For i = 1 To iLastRow > If .Cells(i, "D").Value = rngtrg(m) Then > iNextRow = iNextRow + 1 > .Rows(i).Copy Workbooks("X").Worksheets("sheet1").Cells(iNextRow, > "A").Offset(klstrw + 2, 0) > End If > Next i > End With > > > Any help on this problem will be much appreciated > > Thanks in advance > > Regards > Len
From: Per Jessen on 5 Feb 2010 13:48 Hi Your code does not loop over the values in the array, and you have a fixed destination row in your copy statement: In the statement below, m is a static value while comparing to values in Sheet2. If .Cells(i, "D").Value = rngtrg(m) Then Look at this: Sub bbb() Dim TargetRng As Range Dim SearchRng As Range Dim CopyToCell As Range With Workbooks("X").Worksheets("Sheet1") Set TargetRng = .Range("A1", .Range("A" & Rows.Count).End(xlUp)) Set CopyToCell = .Range("A" & Rows.Count).End(xlUp).Offset(2, 0) End With With Workbooks("WorkbookY.xls").Worksheets("Sheet2") Set SearchRng = .Range("D1", Range("D" & Rows.Count).End(xlUp)) End With For Each cell In TargetRng.Cells For Each c In SearchRng.Cells If cell.Value = c.Value Then c.EntireRow.Copy CopyTo Set CopyToCell = CopyToCell.Offset(1, 0) End If Next Next End Sub Hopes this helps. ... Per On 5 Feb., 17:12, Len <ltong2000...(a)yahoo.co.uk> wrote: > Hi, > > After several attempts to run the codes below, it fails to copy each > row of data in column A of sheet1 from workbookX instead it copied the > last row of data only ( ie only response to last row in this array > "rngtrg(m)" ) > In fact, my intended codes is to copy each row of data in column A of > sheet1 from workbookX and place it in the array, then use each copied > row from the array to search the text string from column D in sheet2 > of another workbook(Y), > If found, it will copy each matched row of data back to column A after > the last used cells, of sheet1 in workbookX > > Extract of codes > > Dim m%, rngtrg$(), klstrw As Long > Dim k As Integer > klstrw = Cells(Rows.Count, "A").End(xlUp).Row > > For k = 1 To klstrw > m = m + 1 > ReDim Preserve rngtrg(1 To m) > rngtrg(m) = Workbooks("X").Worksheets("Sheet1").Cells(k, 1) > Next k > > Windows("WorkbookY.xls").Activate > With Worksheets("Sheet2") > Dim iLastRow As Long, i As Integer > Dim iNextRow As Long > iLastRow = .Cells(.Rows.Count, "D").End(xlUp).Row > For i = 1 To iLastRow > If .Cells(i, "D").Value = rngtrg(m) Then > iNextRow = iNextRow + 1 > .Rows(i).Copy Workbooks("X").Worksheets("sheet1").Cells(iNextRow, > "A").Offset(klstrw + 2, 0) > End If > Next i > End With > > Any help on this problem will be much appreciated > > Thanks in advance > > Regards > Len
From: Len on 6 Feb 2010 10:02 Hi Per, Thanks for your kind response and your suggestion codes It works perfectly ! Hi JL, Thanks for your kind advise and I was a bit confused on how to use offset to replace klstrw variable in this situation It would be great if you could share your codes to use offset method to make the above codes works Thanks again for all your helps Regards Len
From: JLGWhiz on 6 Feb 2010 13:30
Per has already solved the overall problem, but here is what I am referring to: klstrw = Cells(Rows.Count, "A").End(xlUp).Row This line of code refers only to the ActiveSheet so that when you use it here: ..Rows(i).Copy Workbooks("X").Worksheets("sheet1").Cells(iNextRow, "A").Offset(klstrw + 2, 0) The Offset is based on a fixed value from the ActiveSheet, so you could just as well have used a fixed integer value, since "klstrw" has no relevance to the Workbooks("X").Worksheets("sheet1"). "Len" <ltong2000mal(a)yahoo.co.uk> wrote in message news:8830a7c0-48b8-4066-b98d-70e11f9a01fb(a)m35g2000prh.googlegroups.com... > Hi Per, > > Thanks for your kind response and your suggestion codes > It works perfectly ! > > > Hi JL, > > Thanks for your kind advise and I was a bit confused on how to use > offset to replace klstrw variable in this situation > It would be great if you could share your codes to use offset method > to make the above codes works > > Thanks again for all your helps > > Regards > Len > |