From: jdawe on
force = push + pull.

push = solid matter + potential energy

pull = fluid matter + kinetic energy

We have,

a magnet = solid matter.

and

an electric current = kinetic energy.

Therefore,

our opposing operands of electromagnetism are:

solid matter

or

kinetic energy.

In other words,

electromagnetism force = solid matter ( push ) + kinetic energy
( pull ).

-Josh.

From: preedmont on

"jdawe" <mrjdawe(a)gmail.com> wrote in message
news:34932002-33d2-40b7-9b82-139aa9b43849(a)c3g2000yqd.googlegroups.com...
> force = push + pull.
>
> push = solid matter + potential energy
>
> pull = fluid matter + kinetic energy
>
> We have,
>
> a magnet = solid matter.
>
> and
>
> an electric current = kinetic energy.
>
> Therefore,
>
> our opposing operands of electromagnetism are:
>
> solid matter
>
> or
>
> kinetic energy.
>
> In other words,
>
> electromagnetism force = solid matter ( push ) + kinetic energy
> ( pull ).
>
> -Josh.
>

Great! So, where does Gas, and Work fit in ?


From: Ste on
On 16 Jan, 03:14, "preedmont" <nos...(a)spamless.com> wrote:
> "jdawe" <mrjd...(a)gmail.com> wrote in message
>
> news:34932002-33d2-40b7-9b82-139aa9b43849(a)c3g2000yqd.googlegroups.com...
>
>
>
>
>
> > force = push + pull.
>
> > push = solid matter + potential energy
>
> > pull = fluid matter + kinetic energy
>
> > We have,
>
> > a magnet = solid matter.
>
> > and
>
> > an electric current = kinetic energy.
>
> > Therefore,
>
> > our opposing operands of electromagnetism are:
>
> > solid matter
>
> > or
>
> > kinetic energy.
>
> > In other words,
>
> > electromagnetism force = solid matter ( push ) + kinetic energy
> > ( pull ).
>
> > -Josh.
>
> Great!  So, where does Gas, and Work fit in ?

I'm not sure I'd want him doing any gas work! Lol.
From: Ste on
On 16 Jan, 02:00, jdawe <mrjd...(a)gmail.com> wrote:
>
> force = push + pull.

How do we distinguish push from pull?
From: preedmont on

"Ste" <ste_rose0(a)hotmail.com> wrote in message
news:dd68ad12-0046-499a-9391-452eb70953a0(a)a6g2000yqm.googlegroups.com...
> On 16 Jan, 02:00, jdawe <mrjd...(a)gmail.com> wrote:
>>
>> force = push + pull.
>
> How do we distinguish push from pull?

push = - pull

now add pull to both sides

push + pull = 0

therefore, force = 0