From: jdawe on 15 Jan 2010 21:00 force = push + pull. push = solid matter + potential energy pull = fluid matter + kinetic energy We have, a magnet = solid matter. and an electric current = kinetic energy. Therefore, our opposing operands of electromagnetism are: solid matter or kinetic energy. In other words, electromagnetism force = solid matter ( push ) + kinetic energy ( pull ). -Josh.
From: preedmont on 15 Jan 2010 22:14 "jdawe" <mrjdawe(a)gmail.com> wrote in message news:34932002-33d2-40b7-9b82-139aa9b43849(a)c3g2000yqd.googlegroups.com... > force = push + pull. > > push = solid matter + potential energy > > pull = fluid matter + kinetic energy > > We have, > > a magnet = solid matter. > > and > > an electric current = kinetic energy. > > Therefore, > > our opposing operands of electromagnetism are: > > solid matter > > or > > kinetic energy. > > In other words, > > electromagnetism force = solid matter ( push ) + kinetic energy > ( pull ). > > -Josh. > Great! So, where does Gas, and Work fit in ?
From: Ste on 15 Jan 2010 23:29 On 16 Jan, 03:14, "preedmont" <nos...(a)spamless.com> wrote: > "jdawe" <mrjd...(a)gmail.com> wrote in message > > news:34932002-33d2-40b7-9b82-139aa9b43849(a)c3g2000yqd.googlegroups.com... > > > > > > > force = push + pull. > > > push = solid matter + potential energy > > > pull = fluid matter + kinetic energy > > > We have, > > > a magnet = solid matter. > > > and > > > an electric current = kinetic energy. > > > Therefore, > > > our opposing operands of electromagnetism are: > > > solid matter > > > or > > > kinetic energy. > > > In other words, > > > electromagnetism force = solid matter ( push ) + kinetic energy > > ( pull ). > > > -Josh. > > Great! So, where does Gas, and Work fit in ? I'm not sure I'd want him doing any gas work! Lol.
From: Ste on 15 Jan 2010 23:30 On 16 Jan, 02:00, jdawe <mrjd...(a)gmail.com> wrote: > > force = push + pull. How do we distinguish push from pull?
From: preedmont on 15 Jan 2010 23:33 "Ste" <ste_rose0(a)hotmail.com> wrote in message news:dd68ad12-0046-499a-9391-452eb70953a0(a)a6g2000yqm.googlegroups.com... > On 16 Jan, 02:00, jdawe <mrjd...(a)gmail.com> wrote: >> >> force = push + pull. > > How do we distinguish push from pull? push = - pull now add pull to both sides push + pull = 0 therefore, force = 0
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