From: KY on
Eliminate a, b, c;
a + b + c = 0,
((b - c)/a + (c - a)/b + (a - b)/c)*(a/(b - c) + b/(c - a) + c/(a - b)) = k
From: ksoileau on
On Jan 14, 10:15 am, KY <wkfkh...(a)yahoo.co.jp> wrote:
> Eliminate a, b, c;
> a + b + c = 0,
> ((b - c)/a + (c - a)/b + (a - b)/c)*(a/(b - c) + b/(c - a) + c/(a - b)) = k

a = -b-c, k = 9
From: preedmont on

"KY" <wkfkh056(a)yahoo.co.jp> wrote in message
news:1082409701.70238.1263485757008.JavaMail.root(a)gallium.mathforum.org...
> Eliminate a, b, c;
> a + b + c = 0,
> ((b - c)/a + (c - a)/b + (a - b)/c)*(a/(b - c) + b/(c - a) + c/(a - b)) =
> k

trivial, k = sqrt( (a*b-c)*(b*c-a)*(a*c-b))


From: Richard P. Cranium on
Buh.

Low.

Me.


From: Amy on

"KY" <wkfkh056(a)yahoo.co.jp> wrote in message
news:1082409701.70238.1263485757008.JavaMail.root(a)gallium.mathforum.org...
> Eliminate a, b, c;
> a + b + c = 0,
> ((b - c)/a + (c - a)/b + (a - b)/c)*(a/(b - c) + b/(c - a) + c/(a - b)) =
> k

2 equations, 4 unknowns....................
Eliminate KY