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From: rom126 on 9 Mar 2010 11:51
On Sun, 7 Mar 2010 14:18:33 -0800 (PST), bill <b92057(a)yahoo.com> wrote:

>On Mar 4, 12:54�pm, rom...(a)sbcglobal.net wrote:
>> Subj: A regular pattern found in the first 37Million Prime Sums using the log
>> of the golden ratio Lp!
>>
>>
>> For example, the Table's last three Lp+3 steps are:
>>
>> Step:8975619 PN:1.600215E8 PN/Step:17.8285 Sum:6.966776E14 its Lp:71.023491
>>
>> � � � � ----PN/Step:18.0764 Sum:1.127248E15 its Lp:72.023491
>> � � � � PN/Step:18.3240 Sum:1.823926E15 its Lp:73.023492
>>
>> Step:18087624 PN:3.359332E8 PN/Step:18.5725 Sum:2.951174E15 its Lp:74.023492 &
>> 3stepGRO 1.309016E0 and its P^3delta= 2.657e-8
>>
>> � � � � PN/Step:18.8201 Sum:4.775100E15 its Lp:75.023492
>> � � � � ----PN/Step:19.0681 Sum:7.726275E15 its Lp:76.023492
>>
>> Step:36482222 PN:7.046670E8 PN/Step:19.3154 Sum:1.250137E16 its Lp:77.023492 &
>> 3stepGRO 1.309017E0
>>
>> � � � � Where 3stepGRO is 1.250137E16 / (1.250137E16 - 2.951174E15) = 1.309017~
>> � � � � and the PN/Step ratio is �7.0466E8 / 36482222 �= 19.3154
>> � � � � and the unit four step example marked by "----"
>>
>> -----------------------
>>
>> ----------------------Contact Information
>>
>> �See my site for the latest material.
>> <A HREF="http://mister-computer.net/index.htm">WEB Site"</A>
>> RD OMeara Oak Park IL �4 Mar 2010
>>
>>
>> Step:25 PN:9.700000E1 PN/Step:0.0000
>
>PN/step = 97/25 =4.04166666666666667 not 0.0000
>
>> Sum:1.060000E3
>
>Sum = 1058, not 1060
>
>> its Lp:14.476004
>
>How do you arrive at this value?
>
>> 3stepGRO 0.000000E0
>
>How do you get this value?
>
>regards, Bill J

------Thanks for responding Bill

the first few table entries have zero data for some fields
until PN sums are accumulated.

step25 sums to 160 because 2 is used as the 1st PN.

the 3stepgro is merely the sum / (sum - sum[-3] )
which is also near 1 + sine 18deg.

I am going to replace 3stepgro with P^3delta as its so flat.

eg.
Step:18087624 PN:3.359332E8 PN/Step:18.5725 Sum:2.951174E15 its Lp:74.023492
&3stepGRO 1.309016E0 and its P^3delta= 2.657e-8

--
Regards from RD O'Meara
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