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From: Natalie Sin Hwee on 9 Aug 2010 06:20 Dear Mathworks, I have two vectors in a 3D space. By using: theta(bb,cc) = atan2(norm(cross(v1,v2)) , dot(v1,v2) ); but it does not give me information on directionality of the angle Theta. Looking at cart2sph/pol, How can i find the theta/phi and r between two 3dimensional vectors? Thank you Natalie
From: Frédéric Bergeron on 9 Aug 2010 08:28 Hey, D'ont you could use the dot product? u=[0 0 1]; v=[0 1 0]; theta=acosd(dot(u,v)/(norm(u)*norm(v))) return 90 degrees, the angle between the two vectors in 3D... Is that what you want? Fred
From: Natalie Sin Hwee on 9 Aug 2010 10:04 "Frédéric Bergeron" <frederic.bergeron(a)logiag.com> wrote in message <i3os8m$58o$1(a)fred.mathworks.com>... > Hey, > > D'ont you could use the dot product? > > u=[0 0 1]; v=[0 1 0]; > theta=acosd(dot(u,v)/(norm(u)*norm(v))) > > return 90 degrees, the angle between the two vectors in 3D... > Is that what you want? > > Fred Hiya fred, I'm tryna find two angles: 1) x-y plane 2) perpendicular to x-y plane so i can map the location of the 2nd vector Thanks ^^ Natalie
From: Matt J on 9 Aug 2010 10:05 "Natalie Sin Hwee " <sin.ng09(a)imperial.ac.uk> wrote in message <i3okop$9n9$1(a)fred.mathworks.com>... > Dear Mathworks, > > I have two vectors in a 3D space. > By using: > theta(bb,cc) = atan2(norm(cross(v1,v2)) , dot(v1,v2) ); > but it does not give me information on directionality of the angle Theta. ====== v1 and v2 span a plane that cuts R^3 into two half-spaces. In order to set up a system of quadrants in this plane, and define which quadrant theta belongs to, you need some way of deciding which half-space is up and which half-space is down. This will probably require a 3rd vector residing in one of the half-spaces, marking it as up or down. > Looking at cart2sph/pol, > > How can i find the theta/phi and r between two 3dimensional vectors? ======= What's unclear? cart2sph returns these angles explicitly, so can't you get the separation by simple subtraction?
From: Natalie Sin Hwee on 10 Aug 2010 07:22 "Matt J " <mattjacREMOVE(a)THISieee.spam> wrote in message <i3p1v7$cps$1(a)fred.mathworks.com>... > "Natalie Sin Hwee " <sin.ng09(a)imperial.ac.uk> wrote in message <i3okop$9n9$1(a)fred.mathworks.com>... > > Dear Mathworks, > > > > I have two vectors in a 3D space. > > By using: > > theta(bb,cc) = atan2(norm(cross(v1,v2)) , dot(v1,v2) ); > > but it does not give me information on directionality of the angle Theta. > ====== > > v1 and v2 span a plane that cuts R^3 into two half-spaces. In order to set up a system of quadrants in this plane, and define which quadrant theta belongs to, you need some way of deciding which half-space is up and which half-space is down. This will probably require a 3rd vector residing in one of the half-spaces, marking it as up or down. > > > > > Looking at cart2sph/pol, > > > > How can i find the theta/phi and r between two 3dimensional vectors? > ======= > > What's unclear? cart2sph returns these angles explicitly, so can't you get the separation by simple subtraction? If i have a line spanning between: a=[0.5, 0, 1]; b=[0, 0.5, 0]; how can i find the Theta and Phi in relation to the x-y Plane? Thank you Nataile
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