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From: dh on 29 Mar 2010 06:20
Hi,
the Fourier transform for an interval (-Infinity.Infinity) is defined
as: Limit[1/L Integral[...,{x,-L,L}],L->Infinity]
The factor 1/L produces the convergence for Cos[t], Exp[I t] etc. But
not for Exp[t].
Daniel


On 27.03.2010 11:09, ALittleDog wrote:
> Following the previous question, may it be said that a periodic has
> its Fourier transform and a non-periodic function has its Fourier
> transformed iff it is square integrable.
>


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