GMSK recover from I, Q sample data
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From: Pat Z on 26 Feb 2010 19:42 Hi, Suppose in the GMSK receiver side, I got I & Q sample data. Are the following steps able to recover the original data? 1) calculate sqrt(I) + sqrt(Q) = C(t) to obtain the integrated signals 2) differentiate on C(t). This is the adding result of each pulse. 3) Should I remove every pi/2 to get the original data then? thanks pat
From: John on 26 Feb 2010 20:13 On Feb 26, 7:42 pm, Pat Z <patrick....(a)gmail.com> wrote: > Hi, > > Suppose in the GMSK receiver side, I got I & Q sample data. Are the > following steps able to recover the original data? > > 1) calculate sqrt(I) + sqrt(Q) = C(t) to obtain the integrated signals > 2) differentiate on C(t). This is the adding result of each pulse. > 3) Should I remove every pi/2 to get the original data then? > > thanks > pat No
From: Pat Z on 26 Feb 2010 20:24 On Feb 26, 5:13 pm, John <sampson...(a)gmail.com> wrote: > On Feb 26, 7:42 pm, Pat Z <patrick....(a)gmail.com> wrote: > > > Hi, > > > Suppose in the GMSK receiver side, I got I & Q sample data. Are the > > following steps able to recover the original data? > > > 1) calculate sqrt(I) + sqrt(Q) = C(t) to obtain the integrated signals > > 2) differentiate on C(t). This is the adding result of each pulse. > > 3) Should I remove every pi/2 to get the original data then? > > > thanks > > pat > > No Why can't? can you explain a little bit? thanks
From: Jerry Avins on 26 Feb 2010 20:34 Pat Z wrote: > On Feb 26, 5:13 pm, John <sampson...(a)gmail.com> wrote: >> On Feb 26, 7:42 pm, Pat Z <patrick....(a)gmail.com> wrote: >> >>> Hi, >>> Suppose in the GMSK receiver side, I got I & Q sample data. Are the >>> following steps able to recover the original data? >>> 1) calculate sqrt(I) + sqrt(Q) = C(t) to obtain the integrated signals >>> 2) differentiate on C(t). This is the adding result of each pulse. >>> 3) Should I remove every pi/2 to get the original data then? >>> thanks >>> pat >> No > > Why can't? can you explain a little bit? First, don't you mean sqrt(I)^2 + sqrt(Q)^2? Jerry -- Leopold Kronecker on mathematics: God created the integers, all else is the work of man. ����������������������������������������������������������������������
From: Jerry Avins on 26 Feb 2010 20:37
Jerry Avins wrote: > Pat Z wrote: >> On Feb 26, 5:13 pm, John <sampson...(a)gmail.com> wrote: >>> On Feb 26, 7:42 pm, Pat Z <patrick....(a)gmail.com> wrote: >>> >>>> Hi, >>>> Suppose in the GMSK receiver side, I got I & Q sample data. Are the >>>> following steps able to recover the original data? >>>> 1) calculate sqrt(I) + sqrt(Q) = C(t) to obtain the integrated signals >>>> 2) differentiate on C(t). This is the adding result of each pulse. >>>> 3) Should I remove every pi/2 to get the original data then? >>>> thanks >>>> pat >>> No >> >> Why can't? can you explain a little bit? > > First, don't you mean sqrt(I)^2 + sqrt(Q)^2? I meant sqrt(I^2) + sqrt(Q^2). Jerry -- Leopold Kronecker on mathematics: God created the integers, all else is the work of man. ���������������������������������������������������������������������� |