From: Jeff Davis on 17 Jan 2010 17:03 create type y as (c char, n int); select ('a', NULL)::y = ('a', NULL)::y; -- TRUE select ('a', NULL) = ('a', NULL); -- NULL I would expect those to evaluate to the same thing. Regards, Jeff Davis -- Sent via pgsql-hackers mailing list (pgsql-hackers(a)postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
|
Pages: 1 Prev: Git out of sync vs. CVS Next: [HACKERS] AtAbort_Portsl problem |