HELP IF ME YOU CAN!!! Data reduction.
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From: Charles on 27 May 2010 09:36 Again, the data which doesn't look organised when I post it. -2.99 0 -2.4805 0.002 -1.9711 0.009 -1.4616 0.020211 -0.95211 0.037895 -0.44263 0.082421 0.066842 0.17721 0.57632 0.30842 1.0858 0.44874 1.5953 0.58121 2.1047 0.69558 2.6142 0.78242 3.1237 0.84037 3.6332 0.88074 4.1426 0.91695 4.6521 0.95016 5.1616 0.97679 5.6711 0.991 6.1805 0.997 6.69 1 Charles
From: Jonas Lundgren on 27 May 2010 09:50 "Charles " <nkwosman(a)yahoo.com> wrote in message <htlsg5$4nl$1(a)fred.mathworks.com>... > Again, the data which doesn't look organised when I post it. > -2.99 0 > -2.4805 0.002 > -1.9711 0.009 > -1.4616 0.020211 > -0.95211 0.037895 > -0.44263 0.082421 > 0.066842 0.17721 > 0.57632 0.30842 > 1.0858 0.44874 > 1.5953 0.58121 > 2.1047 0.69558 > 2.6142 0.78242 > 3.1237 0.84037 > 3.6332 0.88074 > 4.1426 0.91695 > 4.6521 0.95016 > 5.1616 0.97679 > 5.6711 0.991 > 6.1805 0.997 > 6.69 1 > > Charles Hi Charles, If the first column is uniformly spaced then you need only the first and the last point of this column. Compress by: A = [A(1,1); A(end,1); A(:,2)]; and uncompress by: A = [linspace(A(1),A(2),numel(A)-2)', A(3:end)]; /Jonas
From: Jonas Lundgren on 27 May 2010 09:51 "Charles " <nkwosman(a)yahoo.com> wrote in message <htlsg5$4nl$1(a)fred.mathworks.com>... > Again, the data which doesn't look organised when I post it. > -2.99 0 > -2.4805 0.002 > -1.9711 0.009 > -1.4616 0.020211 > -0.95211 0.037895 > -0.44263 0.082421 > 0.066842 0.17721 > 0.57632 0.30842 > 1.0858 0.44874 > 1.5953 0.58121 > 2.1047 0.69558 > 2.6142 0.78242 > 3.1237 0.84037 > 3.6332 0.88074 > 4.1426 0.91695 > 4.6521 0.95016 > 5.1616 0.97679 > 5.6711 0.991 > 6.1805 0.997 > 6.69 1 > > Charles Hi Charles, If the first column is uniformly spaced then you need only the first and the last point of this column. Compress by: A = [A(1,1); A(end,1); A(:,2)]; and uncompress by: A = [linspace(A(1),A(2),numel(A)-2)', A(3:end)]; /Jonas
From: Charles on 27 May 2010 10:26 I think your suggestion is good. And actually, I am using exactly the same thing already and still used the 2 columns. Thanks a lot. "Jonas Lundgren" <jonas.lundgren(a)saabgroup.com> wrote in message <htltc8$5el$1(a)fred.mathworks.com>... > "Charles " <nkwosman(a)yahoo.com> wrote in message <htlsg5$4nl$1(a)fred.mathworks.com>... > > Again, the data which doesn't look organised when I post it. > > -2.99 0 > > -2.4805 0.002 > > -1.9711 0.009 > > -1.4616 0.020211 > > -0.95211 0.037895 > > -0.44263 0.082421 > > 0.066842 0.17721 > > 0.57632 0.30842 > > 1.0858 0.44874 > > 1.5953 0.58121 > > 2.1047 0.69558 > > 2.6142 0.78242 > > 3.1237 0.84037 > > 3.6332 0.88074 > > 4.1426 0.91695 > > 4.6521 0.95016 > > 5.1616 0.97679 > > 5.6711 0.991 > > 6.1805 0.997 > > 6.69 1 > > > > Charles > > Hi Charles, > If the first column is uniformly spaced then you need only the first and the last point of this column. Compress by: > > A = [A(1,1); A(end,1); A(:,2)]; > > and uncompress by: > > A = [linspace(A(1),A(2),numel(A)-2)', A(3:end)]; > > /Jonas
From: us on 27 May 2010 10:40
"Charles " <nkwosman(a)yahoo.com> wrote in message <htlvds$l2$1(a)fred.mathworks.com>... > I think your suggestion is good. And actually, I am using exactly the same thing already and still used the 2 columns. Thanks a lot. ??? firstly, how is this going to help with respect to your original problem (as stated in the OP)... then, how do you get from your exemplary A1 -> A2 using this approach... us |