From: mohammad alquraan on 28 Mar 2010 16:19 "Arshad Ali" <a.ali(a)lancaster.ac.uk> wrote in message <hflgf6$cu6$1(a)fred.mathworks.com>... > Hi > > I am struggling to create an Hexagonall grid.I need to find the coordinates falling in hexagonal.These point(coordinates) need to be uniform with one metre distance with each point.any body can help me. take this code: clc x=input('enter the value of x: '); y=input('enter the value of y: '); r=input('enter the value of R: '); n=input('enter the value of N: '); d=sqrt(3*n)*r axis([0 x 0 y ]) c=r; v=30:60:390; cv=r*cosd(v); sv=r*sind(v); for y=0:2:y for w=0:2:x line(w*sqrt(3)/2*c+cv,y*1.5*c+sv,'tag','h'); end end for m=1:2:y for k=1:2:x line(k*sqrt(3)/2*c+cv,m*1.5*c+sv,'tag','h'); end end
|
Pages: 1 Prev: hexagonal cell Next: Neural Networks Financial Application Question |