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From: Adam Risi on 25 Feb 2010 01:53
I have been trying to enter the PDE you can see in the picture at:

http://i50.tinypic.com/2rqmx4g.jpg

but I have had absolutely 0 luck. I am trying to solve the eqn into the
form: f(r) = C (aka, solve it for C). Can anyone help me?

From: Patrick Scheibe on 25 Feb 2010 07:44
Hi,

what about

deq = -k/\[ScriptCapitalD] == (1/r^2)*
D[r^2*D[\[ScriptCapitalC][r], r], r]
DSolve[deq, \[ScriptCapitalC], r]

?

Cheers
Patrick

Am Feb 25, 2010 um 7:53 AM schrieb Adam Risi:

> I have been trying to enter the PDE you can see in the picture at:
>
> http://i50.tinypic.com/2rqmx4g.jpg
>
> but I have had absolutely 0 luck. I am trying to solve the eqn into
> the
> form: f(r) = C (aka, solve it for C). Can anyone help me?
>


From: dh on 25 Feb 2010 07:45
Hi Adam,
no big deal. In general you enter a derivative by e.g.:
D[fun[r],r] or fun'[r]
Look it up in the manual.
Your equation then reads:
-k/D == 1/r^2 D[r^2 C'[r], r]
Daniel


On 25.02.2010 07:53, Adam Risi wrote:
> I have been trying to enter the PDE you can see in the picture at:
>
> http://i50.tinypic.com/2rqmx4g.jpg
>
> but I have had absolutely 0 luck. I am trying to solve the eqn into the
> form: f(r) = C (aka, solve it for C). Can anyone help me?
>


--

Daniel Huber
Metrohm Ltd.
Oberdorfstr. 68
CH-9100 Herisau
Tel. +41 71 353 8585, Fax +41 71 353 8907
E-Mail:<mailto:dh(a)metrohm.com>
Internet:<http://www.metrohm.com>


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