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From: Peter Otten on 13 Aug 2010 06:09
blur959 wrote:

> Hi, I tried that, but it doesn't seem to work. My file directory has
> many different files extensions, and I want it to return me a number
> based on the number of files with similar files extensions. But when I
> tried running it, I get many weird numbers. Below is my code i had so
> far and the result.

Use glob.glob() instead of os.listdir() if you are only interested in files
with a specific extension:

>>> import glob
>>> len(glob.glob("*.py"))
42

Peter

From: blur959 on 13 Aug 2010 07:02
On Aug 13, 6:09 pm, Peter Otten <__pete...(a)web.de> wrote:
> blur959 wrote:
> > Hi, I tried that, but it doesn't seem to work. My file directory has
> > many different files extensions, and I want it to return me a number
> > based on the number of files with similar files extensions. But when I
> > tried running it, I get many weird numbers. Below is my code i had so
> > far and the result.
>
> Use glob.glob() instead of os.listdir() if you are only interested in files
> with a specific extension:
>
> >>> import glob
> >>> len(glob.glob("*.py"))
>
> 42
>
> Peter


Hi, I want to make it such that the user inputs a file extension and
it prints the number of similar file extensions out.
I tried doing this:

directory = raw_input("input file directory")
ext = raw_input("input file ext")

file_list = len(glob.glob(ext))
print file_list


And my result was this:
0
which it is suppose to be 11

May I know why? And how do I specify which directory it is searching
the files extension from? I want the user to specify a directory and
it searches the particular directory for the particular file
extensions and prints the number out.
Hope you guys could help.

Thanks
From: Peter Otten on 13 Aug 2010 07:21
blur959 wrote:

> On Aug 13, 6:09 pm, Peter Otten <__pete...(a)web.de> wrote:
>> blur959 wrote:
>> > Hi, I tried that, but it doesn't seem to work. My file directory has
>> > many different files extensions, and I want it to return me a number
>> > based on the number of files with similar files extensions. But when I
>> > tried running it, I get many weird numbers. Below is my code i had so
>> > far and the result.
>>
>> Use glob.glob() instead of os.listdir() if you are only interested in
>> files with a specific extension:
>>
>> >>> import glob
>> >>> len(glob.glob("*.py"))
>>
>> 42
>>
>> Peter
>
>
> Hi, I want to make it such that the user inputs a file extension and
> it prints the number of similar file extensions out.
> I tried doing this:
>
> directory = raw_input("input file directory")
> ext = raw_input("input file ext")
>
> file_list = len(glob.glob(ext))
> print file_list
>
>
> And my result was this:
> 0
> which it is suppose to be 11
>
> May I know why? And how do I specify which directory it is searching
> the files extension from? I want the user to specify a directory and
> it searches the particular directory for the particular file
> extensions and prints the number out.
> Hope you guys could help.

The part of the filename you don't care about has to be replaced with a "*":

import os
import glob
directory = raw_input("directory? ")
ext = raw_input("file extension? ")
pattern = os.path.join(directory, "*" + ext)
matching_files = glob.glob(pattern)
print len(matching_files), "matching files"

Note that you'll learn a lot more when you look up in the documentation how
the functions mentioned actually work instead of coming back here for every
tiny detail. I you don't feel ready yet to understand enough of the Python
documentation, go one step back and work your way through a tutorial or
introductory book. A starting point is here:

http://wiki.python.org/moin/BeginnersGuide/NonProgrammers

Peter

From: Dave Angel on 13 Aug 2010 08:15
blur959 wrote:
> On Aug 13, 6:09 pm, Peter Otten <__pete...(a)web.de> wrote:
>
>> blur959 wrote:
>>
>>> Hi, I tried that, but it doesn't seem to work. My file directory has
>>> many different files extensions, and I want it to return me a number
>>> based on the number of files with similar files extensions. But when I
>>> tried running it, I get many weird numbers. Below is my code i had so
>>> far and the result.
>>>
>> Use glob.glob() instead of os.listdir() if you are only interested in files
>> with a specific extension:
>>
>>
>>>>> import glob
>>>>> len(glob.glob("*.py"))
>>>>>
>> 42
>>
>> Peter
>>
>
>
> Hi, I want to make it such that the user inputs a file extension and
> it prints the number of similar file extensions out.
> I tried doing this:
>
> directory =aw_input("input file directory")
> ext =aw_input("input file ext")
>
> file_list =en(glob.glob(ext))
> print file_list
>
>
> And my result was this:
> 0
> which it is suppose to be 11
>
> May I know why? And how do I specify which directory it is searching
> the files extension from? I want the user to specify a directory and
> it searches the particular directory for the particular file
> extensions and prints the number out.
> Hope you guys could help.
>
> Thanks
>
>
Glob doesn't do much useful unless there's a wildcard. And as you point
out, it also needs the directory. You want to pass it something like
mydirect/*.txt

In your case, you might construct that with something like
os.path.join(directory, "*." + ext)

DaveA

From: blur959 on 13 Aug 2010 10:40
Hi all, I got a problem with my script. Everything looks good so far
but for some reason my os.rename isn't working. Can anyone tell me
why? Hope you guys could help. Thanks.




import os
import glob
directory = raw_input("directory? ")
ext = raw_input("file extension? ")
r = raw_input("replace name")
pattern = os.path.join(directory, "*" + ext)
matching_files = glob.glob(pattern)
file_number = len(matching_files)



for filename in os.listdir(directory):
if ext in filename:
path = os.path.join(directory, filename)
seperated_names = os.path.splitext(filename)[0]
replace_name = filename.replace(seperated_names, r)
split_new_names = os.path.splitext(replace_name)[0]

for pad_number in range(0, file_number):
padded_numbers = "%04d" % pad_number
padded_names = "%s_%s" % (split_new_names, padded_numbers)
newpath = os.path.join(directory, padded_names)
newpathext = "%s%s" % (newpath, ext)


new_name = os.rename(path, newpathext)



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