How to Solve This Code ???
in [Matlab]
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From: Walter Roberson on 25 May 2010 13:33 Samiov wrote: > Walter Roberson <roberson(a)hushmail.com> wrote in message > <O4RKn.10567$%u7.7652(a)newsfe14.iad>... >> if leaving; break; end > Thousands of thanks Walter!!! you really saved my life!!!! :))) > Now it works as I want!!! It was just that thing that I looked > for... It is merely exactly the same thing you had been told several times before, to use a flag to determine whether you had finished your loop.
From: dpb on 25 May 2010 13:50 Samiov wrote: > dpb <none(a)non.net> wrote in message > <htgn7q$7ui$1(a)news.eternal-september.org>... >> Samiov wrote: >> ... >> >> > x2 = find(I(1:x1-2,y1)==1 & I(2:x1-1,y1) == 0, 1, 'last'); >> > y2 = find(I(x1,y1+2:col)==1 & I(x1,y1+1:col-1) == 0, 1, >> 'last'); >> > I1 = I(x2:x1,y1:y2); >> ... >> >> What is it you _really_ want, again? >> >> Unless for each column your x1:x2 extent is the same the result isn't >> going to be a 2D array and the assignment above will abort on >> mismatched array sizes unless you've created an I1 = zeros(size(I)) or >> somesuch in which to contain the subimage. >> >> It still seems as though you could do this whole thing w/o the loops >> or at least by simply processing the results of the find() operations >> in a loop or two in a much more simplistic (and "Matlab'y") manner. >> It appears you're trying to code in Matlab in a C or Fortran manner >> instead of using the features of the language as designed. >> >> I'd harken back to Steve's message of "chill, dood; slow down and >> _think_ a little"... > __________________________________________________________ > Hi dpb, > I've got the solution thanks to Walter Well, I'd posted the same advice at least twice before as well as Walter having done so as well... --
From: Samiov on 25 May 2010 15:09
yeah guys! I see what you mean now by the term "flag"... Sorry for insisting these two days..first I don't know too much the programming lexic & 2nd I don't speak well English..so I have problems of comprehension but I try my best to understand Anyway thanks all of you for offering your help |