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From: Yukiko Shimizu on 17 Jun 2010 11:56
Hello.

Say I have type='xyz'
and C=['xyz' 'xxy 'zyx']
How do I check if type is an element of C? If it is I want it to return a logical 1.

Thank you.
From: Rob Campbell on 17 Jun 2010 12:07
"Yukiko Shimizu" <yk.mizu(a)gmail.com> wrote in message <hvdgik$eoo$1(a)fred.mathworks.com>...
> Hello.
>
> Say I have type='xyz'
> and C=['xyz' 'xxy 'zyx']
> How do I check if type is an element of C? If it is I want it to return a logical 1.

I think you want to use a cell array not the concatenation you show above. Then you'd do:
C={'xyz' 'xxy' 'zyx'};
strmatch('xxy',C)

ans =

2
From: Matt Fig on 17 Jun 2010 12:09
C = ['xyz' 'xxy' 'zyx']
type = 'xyz'
is_type_in_C = any(strfind(C,type))

Note that you may have wanted this instead because string concatenation in C:

C = {'xyz' 'xxy' 'zyx'}
any(ismember(C,type))
From: Yukiko Shimizu on 17 Jun 2010 12:16
"Yukiko Shimizu" <yk.mizu(a)gmail.com> wrote in message <hvdgik$eoo$1(a)fred.mathworks.com>...
> Hello.
>
> Say I have type='xyz'
> and C=['xyz' 'xxy 'zyx']
> How do I check if type is an element of C? If it is I want it to return a logical 1.
>
> Thank you.

Wait, so what is the exact difference between { and [? I always used [ thinking I would be making a matrix.
From: Matt Fig on 17 Jun 2010 12:22
"Yukiko Shimizu" <yk.mizu(a)gmail.com> wrote in message
> Wait, so what is the exact difference between { and [? I always used [ thinking I would be making a matrix.

Well, why not look at it?

% First this one.
C = {'xyz' 'xxy' 'zyx'};
C{1}
C{2}
C{3}
whos C

% Now this one.
C = ['xyz' 'xxy' 'zyx']
C(1:3)
whos C
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