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From: Srikanth K S on 16 Jun 2010 05:36
*Here is a way, but there could be other elegant ways than this!

*In[8]:== mat1=={{1,0,0,0},{2,3,0,0},{4,9,5,0},{2,2,3,4}};
In[12]:== Union@@@MapThread[List,{mat1,MapThread[List,mat1]}]
Out[12]== {{0,1,2,4},{0,2,3,9},{0,3,4,5,9},{0,2,3,4}}*
*---


2010/6/15 dragec <culinovic(a)gmail.com>

> 1 0 0 0
> 2 3 0 0
> 4 9 5 0
> 2 2 3 4
>
From: Alexei Boulbitch on 16 Jun 2010 05:41
Try this:
This is your initial matrix (or alike) in a form of a table

M = {{1, 0, 0, 0}, {2, 3, 0, 0}, {4, 5, 6, 0}, {7, 8, 9, 10}} // Grid


That is what you need:

Table[If[i > j, M[[i, j]], M[[j, i]]], {i, 1, Length[M[[1]]]}, {j, 1,
Length[M[[1]]]}] // Grid

??


please help me with simple to apply function that will construct
symmetric matrix from given just a half matrix with diagonal.
Eg:

From:
1 0 0 0
2 3 0 0
4 9 5 0
2 2 3 4

To give:

1 2 4 2
2 3 9 2
4 9 5 3
2 2 3 4


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Material Development

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From: Srikanth K S on 16 Jun 2010 05:42
*Here it is:

mat1 + Transpose[mat1] - DiagonalMatrix[Diagonal[mat1]]
*---


2010/6/15 Srikanth K S <sriperso(a)gmail.com>

> *Sorry, that seems like a mistake!
> *---
>
>
> 2010/6/15 Srikanth K S <sriperso(a)gmail.com>
>
> *Here is a way, but there could be other elegant ways than this!
>>
>> *In[8]:== mat1=={{1,0,0,0},{2,3,0,0},{4,9,5,0},{2,2,3,4}};
>> In[12]:== Union@@@MapThread[List,{mat1,MapThread[List,mat1]}]
>> Out[12]== {{0,1,2,4},{0,2,3,9},{0,3,4,5,9},{0,2,3,4}}*
>> *---
>>
>>
>> 2010/6/15 dragec <culinovic(a)gmail.com>
>>
>> 1 0 0 0
>>> 2 3 0 0
>>> 4 9 5 0
>>> 2 2 3 4
>>>
>>
>>
From: Srikanth K S on 16 Jun 2010 05:42
*Sorry, that seems like a mistake!
*---


2010/6/15 Srikanth K S <sriperso(a)gmail.com>

> *Here is a way, but there could be other elegant ways than this!
>
> *In[8]:== mat1=={{1,0,0,0},{2,3,0,0},{4,9,5,0},{2,2,3,4}};
> In[12]:== Union@@@MapThread[List,{mat1,MapThread[List,mat1]}]
> Out[12]== {{0,1,2,4},{0,2,3,9},{0,3,4,5,9},{0,2,3,4}}*
> *---
>
>
> 2010/6/15 dragec <culinovic(a)gmail.com>
>
> 1 0 0 0
>> 2 3 0 0
>> 4 9 5 0
>> 2 2 3 4
>>
>
>
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