Hypergeometric2F1
in [Matlab]
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From: Maastricht University de Boer on 11 Aug 2010 11:02 When trying to solve a differential equation in Mathematica I got Hypergeometric2F1[1-(rho/A), 1-(rho/A),-e^(A*t-C[1])*epsilon*lambdaA] as an output. Unfortunately I lack knowledge about hypergeometric functions. Can anybody maybe tell me whether it is possible to turn this output into a 'normal' equation and if so how this can be done? Thanks, Hans
From: us on 11 Aug 2010 11:30 "Maastricht University de Boer" <h.de-boer(a)maastrichtuniversity.nl> wrote in message <i3ue1r$l9e$1(a)fred.mathworks.com>... > When trying to solve a differential equation in Mathematica you are in the wrong NG... us
From: Roger Stafford on 11 Aug 2010 19:59 "Maastricht University de Boer" <h.de-boer(a)maastrichtuniversity.nl> wrote in message <i3ue1r$l9e$1(a)fred.mathworks.com>... > When trying to solve a differential equation in Mathematica I got > > Hypergeometric2F1[1-(rho/A), 1-(rho/A),-e^(A*t-C[1])*epsilon*lambdaA] > > as an output. Unfortunately I lack knowledge about hypergeometric functions. Can anybody maybe tell me whether it is possible to turn this output into a 'normal' equation and if so how this can be done? > > Thanks, > > Hans - - - - - - - - - - - - MathWorks' Symbolic Toolbox has the generalized hypergeometric function 'hypergeom'. As explained in its documentation, if a, b, and c are scalars, then hypergeom([a,b],c,z) gives the Gauss hypergeometric function 2F1 evaluated at a,b,c;z. The Mathematica expression you show seems to have only three arguments. I don't know how they correspond to the four arguments necessary for matlab's Gauss hypergeometric function. See the websites: http://en.wikipedia.org/wiki/Hypergeometric_function http://mathworld.wolfram.com/HypergeometricFunction.html Roger Stafford
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