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From: Claire on 6 Jun 2010 17:51
Hello,
If I have a variable declared as Long:

Dim RingCount as Long

can I do this:
RingCount = Int((Timer - StartDial) / 2)
or should I do this:
RingCount = Abs((Timer - StartDial) / 2)
or do this:
RingCount = (Timer - StartDial) \ 2

Which one will be the best approach?

Thanks,
Claire




From: Bee on 6 Jun 2010 19:01

Well, I would not use Timer since it rolls over at midnight.

Then (also) using Abs() might give you a really bad number if you use Timer.

And what is StartDial declared as?

Timer returns a Single according to Help.

"Claire" wrote:

> Hello,
> If I have a variable declared as Long:
>
> Dim RingCount as Long
>
> can I do this:
> RingCount = Int((Timer - StartDial) / 2)
> or should I do this:
> RingCount = Abs((Timer - StartDial) / 2)
> or do this:
> RingCount = (Timer - StartDial) \ 2
>
> Which one will be the best approach?
>
> Thanks,
> Claire
>
>
>
>
> .
>
From: Claire on 6 Jun 2010 19:41
I am not concerned about Timer rolling over at midnight

StartDial is declared as Single.


"Bee" <Bee(a)discussions.microsoft.com> wrote in message
news:82A55D57-B142-42C1-BB43-01FF3202D219(a)microsoft.com...
>
> Well, I would not use Timer since it rolls over at midnight.
>
> Then (also) using Abs() might give you a really bad number if you use
> Timer.
>
> And what is StartDial declared as?
>
> Timer returns a Single according to Help.
>
> "Claire" wrote:
>
>> Hello,
>> If I have a variable declared as Long:
>>
>> Dim RingCount as Long
>>
>> can I do this:
>> RingCount = Int((Timer - StartDial) / 2)
>> or should I do this:
>> RingCount = Abs((Timer - StartDial) / 2)
>> or do this:
>> RingCount = (Timer - StartDial) \ 2
>>
>> Which one will be the best approach?
>>
>> Thanks,
>> Claire
>>
>>
>>
>>
>> .
>>


From: MikeD on 6 Jun 2010 20:28


"Bee" <Bee(a)discussions.microsoft.com> wrote in message
news:82A55D57-B142-42C1-BB43-01FF3202D219(a)microsoft.com...
>
> Well, I would not use Timer since it rolls over at midnight.
>

Depends on what she's using it for. A "midnight rollover" might never be an
issue.


> Then (also) using Abs() might give you a really bad number if you use
> Timer.

How so? As far as I can see, using Abs would not cause a runtime error. It
might result in erroneous data, but not enough info provided to say if it
would or not.



From: MikeD on 6 Jun 2010 20:32


"Claire" <replyto(a)fra> wrote in message
news:eW9byJcBLHA.5848(a)TK2MSFTNGP06.phx.gbl...
> Hello,
> If I have a variable declared as Long:
>
> Dim RingCount as Long
>
> can I do this:
> RingCount = Int((Timer - StartDial) / 2)
> or should I do this:
> RingCount = Abs((Timer - StartDial) / 2)
> or do this:
> RingCount = (Timer - StartDial) \ 2
>
> Which one will be the best approach?
>


What is that you're ultimately wanting? You can do any of those 3 things,
but without knowing the ultimate goal, it's impossible to tell you which of
those 3 choices, or something else, would be best.



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