From: fortune.bruce on
On Apr 17, 1:22 pm, Risto Lankinen <rlank...(a)gmail.com> wrote:
> On 16 huhti, 00:03, Risto Lankinen <rlank...(a)gmail.com> wrote:
>
>
>
> > On 15 huhti, 17:34, Pubkeybreaker <pubkeybrea...(a)aol.com> wrote:
>
> > > On Apr 14, 10:31 am, Pubkeybreaker <pubkeybrea...(a)aol.com> wrote:
> > > > On Apr 12, 4:51 pm, Risto Lankinen <rlank...(a)gmail.com> wrote:
>
> > > > > No one for instance has
> > > > > referred to prior art when it comes to my method.
>
> > > > This is false.  Dik Winter told you that what you were doing
> > > > was just a (disguised) form of Fermat's Method.   This certainly
> > > > IS a reference to prior art.
>
> > > No comments?  I would be especially interested in comments from
> > > those who felt that I was being a "jerk".
>
> > Lesson learnt #1:  In academia, the form is more important
> > than the substance.
>
> No comments?  I would be especially interested in
> comments from those who felt that I was exhibiting
> "hallmarks of a crank".
>
>  - Risto -

OK. Around here...

It is common, trivial knowledge that to properly "work" mathematics
and be versed and able to do anything correct, that you need to follow
certain guidelines and learn certain facts, reading seminal books and
building on this knowledge using fairly simple structure and
curriculum (I'm not saying math is easy, but the steps to take to get
to more complex math are well known and trivial).

It is common, trivial knowledge that in sci.crypt (and likely
sci.math) that math is taken very seriously because failure in
implementing correctly can have dire consequences. This is not a
forgiving environment for those that exhibit lack of basic math
knowledge that also feel compelled to say "Hey... look what I've
invented"

It is common, trivial knowledge that math utilizes terms which must be
used correctly and be mastered. The true math pros have these
embedded and know them like they know their own name. They use them
correctly as second nature and can use this as knowledge to teach.

It is common, trivial knowledge that those individuals that exhibit a
lack of knowledge of basic math tenets and terms, yet who invent their
own terms and repeat them as something everyone should try and
understand are trouble walking and likely clueless cranks.

It is common, trivial knowledge that when someone clearly clueless
about aspects of math (or crypto) that are very well known is
impervious to correction from multiple experts and continues to
disregard their coaching, that person is very likely a crank.

It is common, trivial knowledge around here that when an individual,
clearly wrong in their thinking, and has been impervious to coaching
from the pros, finally begins their exit that they make sure everyone
knows they'll be back with the same incorrect information packaged in
another way and then feel compelled to state the lessons they've
learned (always in a backhanded way), and in those lessons truly get
it wrong. These persons tend to be close to 100% cranks.

It is common, trivial knowledge that in math (as in other areas) the
form is critical and tightly tied to substance and the ability to
communicate correctly from one person to the next.

All these things seem to have escaped your superfine mind. You feign
surprise, but the crank doth protest too much, methinks.

You claim to be a layman. All that means is you are not a
professional.

You admonish all not to think of you as "uneducated", and recommend we
all hold you "self-educated", but when one is incorrectly, or poorly,
"self-educated" are we not back to approaching "uneducated"?

Two weeks into this and managing to be undeterred by the coaching of
multiple experts, you incorrectly claim no prior art on your
"invention" and almost immediately your argument is squashed by fact
and this doesn't slow you down a bit. This is crank behavior.

Even though you haven't knowledge of somewhat basic math terms, you
continue to use your made-up term "Complex Base Digital Analysis"
like we all should just shut up and study it. Pure crankitude.

I could go on, dude.

Bruce



From: Risto Lankinen on
On 18 huhti, 05:14, fortune.br...(a)gmail.com wrote:
>
> I could go on, dude.

Please do. But before that, I humbly beg you to take
a look at the thread named "FactoriComplex device" in
these same newsgroups (plus comp.theory that you left
out from your reply). Currently (many of) you ignore
my work on the basis that nothing useful can come out
from me. Fine, but what then is a better way to get
my work evaluated by a professional?

I really really really wish that you would take a look
at the article. It describes a constraint-matching
device that can be used to find a square root of a
gaussian integer. What's incredible about it, is that
relaxing a constraint (the red cups - see the article)
turns it into a factoring device. This is paradoxical,
because square root is easy and factoring hard, whilst
relaxing constraints should make the task easier.

<sigh>

- Risto -
From: Tim Little on
On 2008-04-18, Risto Lankinen <rlankine(a)gmail.com> wrote:
> This is paradoxical, because square root is easy and factoring hard,
> whilst relaxing constraints should make the task easier.

Factoring is very easy. It's just slow, for numbers that are very
large. I'm not surprised that relaxing a constraint could turn a slow
square-root finding method into a slow factoring method.


- Tim
From: Risto Lankinen on
On 18 huhti, 05:14, fortune.br...(a)gmail.com wrote:

> I could go on, dude.

Gotcha. I figure it's still OK for me to ask questions.

Question to math experts:

There's an infinite array A of integers. Most elements
of the array are zero, but a finite subset have some
other positive value. All elements obey the following
constraint:

FLOOR(A[n]/2) = SUM(i=1..inf,(A[n-1] MOD 2)*(A[n+1] MOD 2))

How do I prove that the total sum of elements is
a square integer?

- Risto -
From: quasi on
On Fri, 18 Apr 2008 03:43:45 -0700 (PDT), Risto Lankinen
<rlankine(a)gmail.com> wrote:

>On 18 huhti, 05:14, fortune.br...(a)gmail.com wrote:
>
>> I could go on, dude.
>
>Gotcha. I figure it's still OK for me to ask questions.
>
>Question to math experts:
>
>There's an infinite array A of integers. Most elements
>of the array are zero, but a finite subset have some
>other positive value. All elements obey the following
>constraint:
>
>FLOOR(A[n]/2) = SUM(i=1..inf,(A[n-1] MOD 2)*(A[n+1] MOD 2))

Something's wrong with the RHS.

The index variable i doesn't get used.

Presumably, the i'th summand should depend on both i and n.

quasi